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Sergeeva-Olga [200]
2 years ago
7

What types of energy do you acquire when you eat a bowl of hot vegetable soup?

Physics
1 answer:
Aleksandr-060686 [28]2 years ago
8 0

Answer:

you need kinetic energy because it is the energy that is used when In motion

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A glass falls from a table top and smashes on the floor 0.6 seconds later. How high is the table?
soldi70 [24.7K]

Answer:

1.8 m

Explanation:

Given: Glass falls from a table, smashes 0.6 seconds later

To find: How high a table is

Formula: Vv=gt, dv=1/2gt^2, t=2d/g

Solution: A table's <em>height</em> is measured from the top of the edge down to the floor. The tables are shown both have a height of 30 inches, which is common for many tables.

<u>Data</u>

  • t = 0.6s
  • g = 9.81 m/s²
  • d = ?

<u>Equation</u>

  • d = \frac{1}{2}gt²

<u>Math & Units</u>

  • d = 4.905 (0.6²)
  • d = 442.676

Hence the table is 1.8 m high

5 0
3 years ago
PLEASE HURRY, I'M BEING TIMED!
spayn [35]

Option D is correct. The speed at which the earth's surface moves because of the earth's rotation will then be equivalent to -10³ km/hr

Speed is a body is defined as the ratio of the distance with respect to the time taken by the body. Mathematically:

Speed = Distance/Time

GIven the following

Distance = 104km/hr

If it is 6:00 p.m. in New York, it is 7:00 a.m. of the next day of the week in Tokyo, this means that the time difference between New York and Tokyo is 11 hours.

Time = -11 hours

Get the required speed

Speed = 104/-11

Speed = -9.454545

Speed = -10km/hr

The speed at which the earth's surface moves because of the earth's rotation will then be equivalent to -10³ km/hr

Learn more here: brainly.com/question/2583051

4 0
2 years ago
Read 2 more answers
An object is projected from the ground with an upward speed of ų m/s has a speed of 23m/s when it is at a height of 5m above the
vovikov84 [41]

Answer:

25.08m/s

Explanation:

mgh1 + 0.5mv1² = mgh2 + 0.5mv2²

h1 = 0m

v1 = u

h2 = 5m

v2 = 23m/s

putting the values into the formula above;

m(10)(0) + 0.5m(u²) = m(10)(5) + 0.5m(23²)

0 + 0.5mu² = 50m + 264.5m

0.5mu² = 314.5m

dividing through by m

0.5u² = 314.5

u² = 629

u = <u>2</u><u>5</u><u>.</u><u>0</u><u>8</u><u>m</u><u>/</u><u>s</u>

<u>Theref</u><u>ore</u><u>,</u><u> </u><u>the</u><u> </u><u>init</u><u>ial</u><u> </u><u>speed</u><u> </u><u>"</u><u>u</u><u>"</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u>m</u><u>/</u><u>s</u>

6 0
2 years ago
A large balloon of mass 210 kg is filled with helium gas until its volume is 329 m3. Assume the density of air is 1.29 kg/m3 and
Nastasia [14]

(a) See figure in attachment (please note that the image should be rotated by 90 degrees clockwise)

There are only two forces acting on the balloon, if we neglect air resistance:

- The weight of the balloon, labelled with W, whose magnitude is

W=mg

where m is the mass of the balloon+the helium gas inside and g is the acceleration due to gravity, and whose direction is downward

- The Buoyant force, labelled with B, whose magnitude is

B=\rho_a V g

where \rho_a is the air density, V is the volume of the balloon and g the acceleration due to gravity, and where the direction is upward

(b) 4159 N

The buoyant force is given by

B=\rho_a V g

where \rho_a is the air density, V is the volume of the balloon and g the acceleration due to gravity.

In this case we have

\rho_a = 1.29 kg/m^3 is the air density

V=329 m^3 is the volume of the balloon

g = 9.8 m/s^2 is the acceleration due to gravity

So the buoyant force is

B=(1.29 kg/m^3)(329 m^3)(9.8 m/s^2)=4159 N

(c) 1524 N

The mass of the helium gas inside the balloon is

m_h=\rho_h V=(0.179 kg/m^3)(329 m^3)=59 kg

where \rho_h is the helium density; so we the total mass of the balloon+helium gas inside is

m=m_h+m_b=59 kg+210 kg=269 kg

So now we can find the weight of the balloon:

W=mg=(269 kg)(9.8 m/s^2)=2635 N

And so, the net force on the balloon is

F=B-W=4159 N-2635 N=1524 N

(d) The balloon will rise

Explanation: we said that there are only two forces acting on the balloon: the buoyant force, upward, and the weight, downward. Since the magnitude of the buoyant force is larger than the magnitude of the weigth, this means that the net force on the balloon points upward, so according to Newton's second law, the balloon will have an acceleration pointing upward, so it will rise.

(e) 155 kg

The maximum additional mass that the balloon can support in equilibrium can be found by requiring that the buoyant force is equal to the new weight of the balloon:

W'=(m'+m)g=B

where m' is the additional mass. Re-arranging the equation for m', we find

m'=\frac{B}{g}-m=\frac{4159 N}{9.8 m/s^2}-269 kg=155 kg

(f) The balloon and its load will accelerate upward.

If the mass of the load is less than the value calculated in the previous part (155 kg), the balloon will accelerate upward, because the buoyant force will still be larger than the weight of the balloon, so the net force will still be pointing upward.

(g) The decrease in air density as the altitude increases

As the balloon rises and goes higher, the density of the air in the atmosphere decreases. As a result, the buoyant force that pushes the balloon upward will decrease, according to the formula

B=\rho_a V g

So, at a certain altitude h, the buoyant force will be no longer greater than the weight of the balloon, therefore the net force will become zero and the balloon will no longer rise.

4 0
3 years ago
When is a hypothesis developed in the scientific method?
ivanzaharov [21]

Answer:

aren't there pics ?

Explanation:

7 0
3 years ago
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