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devlian [24]
3 years ago
7

Which statement supports one of Dalton's contributions to the atomic theory?

Chemistry
2 answers:
Mnenie [13.5K]3 years ago
6 0
<span>C) The element nitrogen is made up of carbon and nitrogen</span>
Readme [11.4K]3 years ago
4 0
The right answer is B)
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If you change the subscripts it would change the reactants or products and then you would be solving a different formula, you would change what the chemical is
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Why do strong bonds exist between water molecules? They have nonpolar structure. They are held together by hydrogen bonds. The h
Zolol [24]

Answer:

They are held together by hydrogen bonds

Explanation:

Hydrogen bonds are special dipole-dipole attractions between polar molecules in which a hydrogen atom is directly joined to a highly electronegative atom(oxygen or nitorgen or fluorine).

Such molecules includes water, alkanoic acids, ammonia and amines.

A hydrogen nucleus has a high concentration of positive charge. The bond is actually an electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom(O or N or F).

Hydrogen bonds are very effective in binding molecules into larger units. Most substances that joins with hydrogen bonds have a higher boiling point and lower volatility.

This is why we have a strong intermolecular bond between water molecules.

5 0
3 years ago
A type of reaction that occurs when oxygen combines with iron to form rust
fiasKO [112]
Oxidation
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3 years ago
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What is the name of this molecule ?
myrzilka [38]
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4 0
3 years ago
The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

7 0
2 years ago
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