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lord [1]
3 years ago
13

The enthalpy change for the explosion of ammonium nitrate with fuel oil is –7198 kJ for every 3 moles of NH4NO3. What is the ent

halpy change for 1.0 mole of NH4NO3 in this reaction?
Chemistry
1 answer:
anastassius [24]3 years ago
7 0

Answer:

−2399.33 kJ

Explanation:

If NH₄NO₃ reacts with fuel oil to give a ΔH of -7198 for every 3 moles of NH₄NO₃

What is the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction

∴ For every 1 mole, we will have \frac{1}{3} of the total enthaply of the 3 moles

so, to determine the 1 mole; we have:

\frac{1}{3}*(-7198kJ)

= −2399.33 kJ

∴ the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction = −2399.33 kJ

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When 16.4 g of steam at 100°C condenses how much heat is released?
OLEGan [10]

Answer:

37064 J

Explanation:

Data Given:

mass of Steam (m) = 16.4 g

heat released (Q) = ?

Solution:

This question is related to the latent heat of condensation.

Latent heat of condensation is the amount of heat released when water vapors condenses to liquid.

Formula used

            Q = m x Lc . . . . . (1)

where

Lc = specific latent heat of condensation

Latent heat of  vaporization of water is exactly equal to heat of condensation with - charge

So, Latent heat of  vaporization of water have a constant value

Latent heat of  vaporization of water = 2260 J/g

So

Latent heat of condensation of water will be = - 2260 J/g

Put values in eq. 1

          Q = (16.4 g) x (- 2260 J/g)

          Q = - 37064 J

So,  37064 J of heat will be released negative sign indicate release of energy

4 0
3 years ago
No, since the slopes are different.
beks73 [17]

Option C, slopes are same but y intercepts are different is the correct answer

5 0
3 years ago
Chen drew a diagram to compare the ways in which different organisms obtain nitrogen. Which label belongs in the area marked z?
Elan Coil [88]

Answer:

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Explanation:

Plants(a.k.a. Producers) obtain nitrogen(N) from the soil by absorption through their roots.

6 0
4 years ago
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The common name is laundry bleach

Hope this helps
3 0
4 years ago
If 6.0 g of fe(co)5 reacts with 4.0 g of pf3 and 4.0 g of h2, which is the limiting reagent
sveticcg [70]
<span>Number of moles of Fe(CO)5 = mass/molar mass = (6.0 g) / (195.8955 g/mol) = 0.03 mol Number of moles of PF3 = (4.0 g)/ (87.97 g/mol) = 0.0455 mol Number of moles of H2 = (4.0 g) / (2.016 g/mol) = 1.984 mol From the balanced equation 1 mol of Fe(CO)5 reacts with 2 mol of PF3 and 1 mol of H2 then 0.03 mol of Fe(CO)5 will need 0.03 (2/1) = 0.06 mol of PF3 and 0.03 mol of H2 Since we have less PF3 ( 0.0455 mol instead of 0.06 mol), that is the limiting agent</span>
5 0
3 years ago
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