A small 23 kilogram canoe is floating downriver at a speed of 3 m/s. What is the canoe's kinetic energy?
1 answer:
Kinetic energy is defined as the energy the object possess due to its motion. It is the work that accelerates a given body from rest to motion.
Given:
The mass of the canoe is 23 kilogram
The velocity of the canoe is 3 m/s
The kinetic energy can be given by the formula:
KE = ![\frac{1}{2}.m.v^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D.m.v%5E%7B2%7D)
Substituting the given values in the kinetic energy equation
KE =![\frac{1}{2}.(23kg).(3m/s)^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D.%2823kg%29.%283m%2Fs%29%5E%7B2%7D)
KE= 11.5 * 9 kg.m^2/s^2
k = 103.5 J
Therefore the kinetic energy of the canoe is 103.5 Joules.
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a) Addition reaction, is your answer
Answer:
![\large \boxed{\text{-10.0 kJ}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctext%7B-10.0%20kJ%7D%7D)
Explanation:
1. Calculate the work
w = - pΔV = -4.3 atm × (43 L - 20 L) = -4.3 × 23 L·atm = -98.9 L·atm
2. Convert litre-atmospheres to joules
![w = \text{-98.9 L\cdot$atm } \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm }} = \text{-10000 J} = \textbf{-10.0 kJ}\\\\\text{The work done is $\large \boxed{\textbf{-10.0 kJ}}$}](https://tex.z-dn.net/?f=w%20%3D%20%5Ctext%7B-98.9%20L%5Ccdot%24atm%20%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B101.3%20J%7D%7D%7B%5Ctext%7B1%20L%24%5Ccdot%24atm%20%7D%7D%20%3D%20%5Ctext%7B-10000%20J%7D%20%3D%20%5Ctextbf%7B-10.0%20kJ%7D%5C%5C%5C%5C%5Ctext%7BThe%20work%20done%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B-10.0%20kJ%7D%7D%24%7D)
The negative sign indicates that the work was done against the surroundings.
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hey there!:
density = 75.0 g/mL
Volume = 12 mL
mass = ?
Therefore:
D = m / V
75.0 =m / 12
m = 75.0 * 12
m = 900 g
Answer B
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