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dusya [7]
3 years ago
15

The empirical formula for a compound is c2h5 and its formula mass is 58 amu. what is its molecular formula?

Chemistry
2 answers:
Nat2105 [25]3 years ago
4 0
Molecular formula of compound is C4H10
jasenka [17]3 years ago
4 0

Answer: C_4H_{10}

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

To calculate the molecular formula, we need to find the valency which is multiplied by each element to get the molecular formula.

Given empirical formula is C_2H_5 Empirical mass =2\times 12+1\times 5=29amu

The equation used to calculate the valency is:

n=\frac{\text{molecular mass}}{\text{empirical mass}}=\frac{58}{29}=2

The molecular formula will be C_2H_5\times 2=C_4H_{10}

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What is the molarity of a solution that contains 87.75g of NaCI in 500.ml of solution
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Answer:

M = 3.0 mol/L.

Explanation:

  • We can calculate the molarity of a solution using the relation:

<em>M = (mass x 1000) / (molar mass x V)</em>

  • M is the molarity "number of moles of solute per 1.0 L of the solution.
  • mass is the mass of the solute (g) (m = 87.75 g of NaCl).
  • molar mass of NaCl = 58.44 g/mol.
  • V is the volume of the solution (ml) (V = 500.0 ml).

∴ M = (mass x 1000) / (molar mass x V) = (87.75 g x 1000) / (58.44 g/mol x 500.0 ml) = 3.0 mol/L.

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3 years ago
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8 0
2 years ago
2. Calculate the molarity of a solution if there are 1.5 mol of NaCl in 2.3 L of solution.
rodikova [14]

Answer:

0.65 M

Explanation:

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In other words, M = moles of substance / liters of solution

Since you're already given the moles of NaCl and the volume of the solution, you can plug those into the equation.

M = moles of NaCl / liters of solution

M = 1.5 mol NaCl / 2.3 L

M = 0.65 mol/L (or 0.65 M)

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6 0
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Explanation:

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