Answer:
The concentration of chloride ion is ![2.82\times10^{-3}\;mol/L](https://tex.z-dn.net/?f=2.82%5Ctimes10%5E%7B-3%7D%5C%3Bmol%2FL)
Explanation:
We know that 1 ppm is equal to 1 mg/L.
So, the
content 100 ppm suggests the presence of 100 mg of
in 1 L of solution.
The molar mass of
is equal to the molar mass of Cl atom as the mass of the excess electron in
is negligible as compared to the mass of Cl atom.
So, the molar mass of
is 35.453 g/mol.
Number of moles = (Mass)/(Molar mass)
Hence, the number of moles (N) of
present in 100 mg (0.100 g) of
is calculated as shown below:
![N=\frac{0.100\;g}{35.453\;g/mol}=2.82\times 10^{-3}\;mol](https://tex.z-dn.net/?f=N%3D%5Cfrac%7B0.100%5C%3Bg%7D%7B35.453%5C%3Bg%2Fmol%7D%3D2.82%5Ctimes%2010%5E%7B-3%7D%5C%3Bmol)
So, there is
of
present in 1 L of solution.
Solids have particles that stay in place and vibrate (least energy)
Liquids have enough energy to slide past each other and have no definite shape.
Gas has a lot of energy and moves freely with no certain shape or volume
Answer: The boiling point of a 3.70 m solution of phenol in benzene is ![89.5^0C](https://tex.z-dn.net/?f=89.5%5E0C)
Explanation:
Elevation in boiling point:
![\Delta T_b=i\times k_b\times m](https://tex.z-dn.net/?f=%5CDelta%20T_b%3Di%5Ctimes%20k_b%5Ctimes%20m)
where,
= change in boiling point
i= vant hoff factor = 1 (for benzene which is a non electrolyte )
= boiling point constant = ![2.53^0C/kgmol](https://tex.z-dn.net/?f=2.53%5E0C%2Fkgmol)
m = molality = 3.70
![T_{solution}-T_{solvent}=i\times k_b\times m](https://tex.z-dn.net/?f=T_%7Bsolution%7D-T_%7Bsolvent%7D%3Di%5Ctimes%20k_b%5Ctimes%20m)
![T_{solution}-80.1^0C=1\times 2.53\times 3.70](https://tex.z-dn.net/?f=T_%7Bsolution%7D-80.1%5E0C%3D1%5Ctimes%202.53%5Ctimes%203.70)
![T_{solution}=89.5^0C](https://tex.z-dn.net/?f=T_%7Bsolution%7D%3D89.5%5E0C)
Thus the boiling point of a 3.70 m solution of phenol in benzene is ![89.5^0C](https://tex.z-dn.net/?f=89.5%5E0C)
A Lithium atom that has lost ONE Electron, is called a Lithium Ion (Li+).