The answer is letter D. Reactants, Products
The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g
<h3>
What is the use of aluminium chloride ?</h3>
Aluminum chloride is useful for the treatment of palmar, plantar, and axillary hyperhidrosis.
Aluminum chloride has also been reported to be useful in facial and scalp hyperhidrosis
The balanced chemical equation represents the mole ratio in which the chemicals combine.
In this case, illustrates that 2 mol Al produces 2 mol Al Cl₃, hence these 2 chemicals are in a 1:1 ratio.
Thus, to produce 8.70 mol aluminium chloride, it will require 8.70 mol aluminium.
But this quantity of Al has a mass in grams of
m = n × Mr
= 8.70 mol × 27g/mol
= 234.9 g
Hence, The weight of aluminum are required to produce 8.70 moles of aluminum chloride is 234.9 g
Learn more about mole concept here ;
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Answer:
1.54grams
Explanation:
Molarity of a solution = n/V
Where;
n = number of moles (mol)
V = volume (L)
Based on the information given in this question;
Volume of NaOH solution = 5.0 × 10ml
= 50ml = 50/1000 = 0.050 L
Molarity = 0. 77 M
Using; Molarity = n/V
0.77 = n/0.05
n = 0.77 × 0.05
n = 0.0385mol
To find the mass (grams) of NaOH in the solution, we use the following formula:
mole (n) = mass/molar mass
Molar mass of NaOH = 23 + 1 + 16 = 40g/mol
0.0385 = mass/40
mass = 0.0385 × 40
mass = 1.54grams.
