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Whitepunk [10]
2 years ago
7

.ASAPPP

Chemistry
1 answer:
kati45 [8]2 years ago
5 0

Answer:

b

Explanation:

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1) Your nephew rides a kiddy train at the local carnival. The train, which has
katrin [286]
<h3>Answer:</h3>

Velocity is 1 m/s

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of the kiddy train is 1000 kg
  • Radius of the curve is 5.0 m
  • Centripetal force is 2000 N

We are required to determine the maximum speed of the train.

  • Centripetal force refers to the force experienced by an object in a circular motion towards the center of a circular path.
  • It is calculated by the formula;
  • Fc=\frac{Mv^{2} }{r}, where m is the mass, v is the velocity and r is the radius of the circular path.
  • Therefore, using the formula we can find the maximum speed.
  • Rearranging the formula;

v=\sqrt{\frac{Fc.r}{m} }

  • Therefore;

v=\sqrt{\frac{(2000N)(5.0m)}{1000kg} }

v=\sqrt{1}

v=1m/s

Therefore, the maximum speed of the train is 1 m/s

6 0
3 years ago
Hydrogen is prepared commercially by the reaction of methane and water vapor at elevated temperatures. CH4 (g) + H2 O(g) ⇌ 3H2 (
Damm [24]

Answer:

6.28

Explanation:

Let's consider the following reaction at equilibrium.

CH₄(g) + H₂O(g) ⇌ 3 H₂(g) + CO(g)

The concentration equilibrium constant (Kc) is the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients.

Kc = [H₂]³ × [CO] / [CH₄] × [H₂O]

Kc = 1.15³ × 0.126 / 0.126 × 0.242

Kc = 6.28

8 0
3 years ago
If you have 3.48 x 1023 formula units of Lead (II) Permanganate, what is its mass?
Tanya [424]

Answer:

\large \boxed{\text{257 g}}

Explanation:

We can convert the formula units to moles and then use the molar mass to find the mass.

1. Moles of Pb(MnO₄)₂

n = 3.48 \times 10^{23}\text{ formula units} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ formula units}} = \text{0.5779 mol}

 

2. Mass of Pb(MnO₄)₂

\text{Mass} = \text{0.5779 mol} \times \dfrac{\text{445.07 g}}{\text{1 mol u}} = \text{257 g}\\\\\text{The mass of lead(II) permanganate is $\large \boxed{\textbf{257 g}}$}

4 0
3 years ago
25. 0 ml of a 0. 100 m solution of NH3 is titrated with 0. 250m HCl. After 10. 0 ml of the hcl has been added, the resultant sol
AveGali [126]

Main Answer: The resultant solution will have 0.125M of HCl.

Explanation:

Given:

Volume of NH3  V1= 25ml = 0.025lit

Molar concentration of NH3  M1= 0.1M

It is titrated with HCl

Molar concentration of HCl M2= 0.25M

Volume of HCl  V2= ?ml

At equilibrium,

M1V1 = M2V2

V2 = M1V1/M2

V2 = (0.1*0.025)/0.25

V2= 0.01lit =0.01*1000 = 10ml

Number of moles = M2*V2 = 0.25 * 0.01 = 0.0025

Now 10ml of HCl is added.

then,

V2 = 10 + 10 = 20ml

Molar concentration of HCl = number of moles/Volume

                                               = 0.0025/0.02

                                               = 0.125M

The resultant solution will have 0.125M of HCl.

To know more about resultant solution, please visit:

brainly.com/question/20367152

#SPJ4

5 0
11 months ago
Whag is the answer. please i need help​
icang [17]

Answer:

First option

Explanation:

Students 1 and 2 have precise measures yet is is not accurate since they measure around 5.

5 0
3 years ago
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