Answer should be 1.5 M given that M is the SI unit for molarity!
Answer:
Molecular
Explanation:
Using the rules for the nomenclature for naming binary covalent (molecular) compounds, the compound SO3 is named sulfur trioxide. The prefix tri- indicates that the oxygen has a subscript of 3 and that a molecule of sulfur trioxide has three oxygen atoms.
Answer:
a. spontaneous
Explanation:
Hello,
In this case, since the Gibbs free energy is a metric that allows us to know whether a chemical reaction is spontaneous (Gibbs free energy less than 0) or nonspontaneous (Gibbs free energy greater than 0) we can mathematically define it as:
Thus, if the enthalpy is negative and the entropy is negative, the subtraction become always negative, for which the Gibbs free energy is negative as well, therefore, based on the aforementioned, any process with a negative change in enthalpy and a positive change in entropy will be: a. spontaneous.
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Answer:
310.53 g of Cu.
Explanation:
The balanced equation for the reaction is given below:
CuSO₄ + Zn —> ZnSO₄ + Cu
Next, we shall determine the mass of CuSO₄ that reacted and the mass Cu produced from the balanced equation. This can be obtained as follow:
Molar mass of CuSO₄ = 63.5 + 32 + (16×4)
= 63.5 + 32 + 64
= 159.5 g/mol
Mass of CuSO₄ from the balanced equation = 1 × 159.5 = 159.5 g
Molar mass of Cu = 63.5 g/mol
Mass of Cu from the balanced equation = 1 × 63.5 = 63.5 g
Summary:
From the balanced equation above,
159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.
Finally, we shall determine the mass of Cu produced by the reaction of 780 g of CuSO₄. This can be obtained as follow:
From the balanced equation above,
159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.
Therefore, 780 g of CuSO₄ will react to produce = (780 × 63.5)/159.5 = 310.53 g of Cu.
Thus, 310.53 g of Cu were obtained from the reaction.
Answer:
C3H3O
Explanation:
Now, what we need to do is to divide the percentage compositions by the relative atomic masses.
The relative atomic mass of carbon 12, the relative atomic mass of hydrogen is 1 while the atomic mass of oxygen is 16.
We now do the divisions as follows:
Carbon = 63.15/12 = 5.2625
Oxygen = 31.55/16 = 1.971875
Hydrogen = 5.30/1 = 5.30
Now,we now divide by the smallest I.e that of oxygen.
Carbon = 5.2625/1.971875 = 2.668
Oxygen = 1.971875/1.971875 = 1
Hydrogen = 5.3/1.971875= 2.688
We can round up the ratio of carbon and hydrogen to 3.
Thus, the empirical formula is C3H3O
