Answer:
Explanation:
Speed of the source of sound = v = 44.7 m/s
Speed of sound = V = 343 m/s
a) Apparent frequency as the train approaches = f = [V /(V -v) ] × f
= [343 / (343 - 44.7) ] × 415 = 477.18 Hz
Wave length = λ = v / f = 343 / 477.18 = 0.719 m
b) Frequency heard as the train leaves = f ' = [V / ( V + v) ] f
= [343 / { 343 + 44.7 ) ] x 415
= 367.2 Hz
Wavelength when leaving = v / f = 343 / 367.2 = 0.934 m
Answer:
<h2>
HIGHER & MORE OR LARGER OR MORE </h2>
HENCE, THE ANSWER IS A. :)
Explanation:
<em><u>#</u></em><em><u>CARRYONLEARNING</u></em>
<em><u>BRAINLIEST</u></em><em><u> </u></em><em><u> </u></em><em><u>PLEASE</u></em><em><u> </u></em><em><u>I </u></em><em><u>REALLY </u></em><em><u>NEED</u></em><em><u> </u></em><em><u>IT</u></em>
There doesn't seem to be any direct connection.
Answer:
I don't think so because we can't breathe in space
Explanation: