A 90.0 kg man climbs hand over hand up a rope to a height of 9.47 m. How much potential energy does he have at the top?

A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 86.0 m/s2

Harman [31]

<span>When the fuel of the rocket is consumed, the acceleration would be zero. However, at this phase the rocket would still be going up until all the forces of gravity would dominate and change the direction of the rocket. We need to calculate two distances, one from the ground until the point where the fuel is consumed and from that point to the point where the gravity would change the direction.

Given:
a = 86 m/s^2
t = 1.7 s

Solution:

d = vi (t) + 0.5 (a) (t^2)
d = (0) (1.7) + 0.5 (86) (1.7)^2
d = 124.27 m

vf = vi + at
vf = 0 + 86 (1.7)
vf = 146.2 m/s (velocity when the fuel is consumed completely)

Then, we calculate the time it takes until it reaches the maximum height.
vf = vi + at
0 = 146.2 + (-9.8) (t)
t = 14.92 s

Then, the second distance
d= vi (t) + 0.5 (a) (t^2)
d = 146.2 (14.92) + 0.5 (-9.8) (14.92^2)
d = 1090.53 m

Then, we determine the maximum altitude:
d1 + d2 = 124.27 m + 1090.53 m = 1214.8 m</span>

5 0

3 years ago

Two stones resembling diamonds are suspected of being fakes. To determine if the stones might be real, the mass and volume of ea

dimaraw [331]

Answer:

stone A is diamond.

Explanation:

given,

Volume of the two stone = 0.15 cm³

Mass of stone A = 0.52 g

Mass of stone B = 0.42 g

Density of the diamond = 3.5 g/cm³

So, to find which stone is gold we have to calculate the density of both the stone.

We know,

$density$ $\density = \dfrac{mass}{volume}$

density of stone A

$\rho_A = \dfrac{0.52}{0.15}$

$\rho_A = 3.467\ g/cm^3$

density of stone B.

$\rho_B = \dfrac{0.42}{0.15}$

$\rho_B = 2.8\ g/cm^3$

Hence, the density of the stone A is the equal to Diamond then stone A is diamond.

6 0

3 years ago

An object is 30 cm in front of a converging lens with a focal length of 10 cm. Use ray tracing to determine the location of the

poizon [28]

Answer:

Inverted

Real

Explanation:

u = Object distance = 30 cm

v = Image distance

f = Focal length = 10 cm

Lens Equation

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{10}-\frac{1}{30}\\\Rightarrow \frac{1}{v}=\frac{1}{15}\\\Rightarrow v=15\ cm$

As, the image distance is positive the image is real and forms on the other side of the lens

$m=-\frac{v}{u}\\\Rightarrow m=-\frac{-15}{30}\\\Rightarrow m=-0.5$

As, the magnification is negative the image is inverted

3 0

3 years ago

A plane travels 4.0 km at an angle of 25◦ to the ground, then changes direction and travels 10 km at an angle of 16◦ to the grou

Maslowich

Answer:

6.1 km

Explanation:

Given that a plane travels 4.0 km at an angle of 25◦ to the ground, then changes direction and travels 10 km at an angle of 16◦ to the ground. What is the magnitude of the plane's total displacement? Answer in units of km

The magnitude of the total displacement D can be calculated by using cosine formula

Ø = 25 - 16 = 9 degree

D^2 = 4^2 + 10^2 - 2 × 4 × 10 × cos 9

D^2 = 16 + 100 - 80cos9

D^2 = 116 - 79.02

D = sqrt( 36.98)

D = 6.1 m

Therefore, the magnitude of the plane's total displacement is 6.1 km

5 0

2 years ago

Osteosarcoma cases are rare. Why does this

Hoochie [10]

Answer:

The answer is: It is difficult to tell if fluoride causes this cancer

Explanation:

edgenuite said

8 0

3 years ago