Answer:
The annual difference in the cost between the two cars in gasoline plus monthly payment per month will be $856.67.
Step-by-step explanation:
Car option "A" gets 18 miles per gallon of gas (MPG) and has a monthly payment of $368.
Now, yearly 12000 miles will consume
gallons of gas.
Now, if the gas costs $2.89 par gallons, then yearly fuel cost is $(666.67 × 2.89) = $1926.67
Hence, the yearly cost for option A will be $(1926.67 + 368 × 12) = $6342.67.
Now, car option "B" is a hybrid and gets 60 MPG with a monthly payment of $409.
Now, yearly 12000 miles will consume
gallons of gas.
Now, if the gas costs $2.89 par gallons, then yearly fuel cost is $(200 × 2.89) = $578
Hence, the yearly cost for option B will be $(578 + 409 × 12) = $5486.
So, the annual difference in the cost between the two cars in gasoline plus a monthly payment per month will be $(6342.67 - 5486) = $856.67. (Answer)
Answer:
9.26
Step-by-step explanation:
you add and you get 9.26
Answer: C
First you have to get rid of the 8 because it is a constant. -4-8=-12. Then, you multiply out the denominator to isolate the variable. This means -12*3=-36
It's 26×10×10×10 because there are 26 possibilities (a-z) for the first letter and 10 possibilities (0-9) for each number. That makes the answer 26,000.
To solve this problem we can use equation.
If we assume that x is number of crocodiles, we can say that number of alligators is 4*x because its 4 times more.
We know that together is 40, so we have
x+4*x=40
Now we are reducing.
5x=40 /:5 dividing both sides by 5
x=9 - number of alligators