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kondor19780726 [428]
4 years ago
12

How many grams of CaCl2 should be dissolved in 633.1 mL of water to make a 0.35 M solution of CaCl2?

Chemistry
1 answer:
Bumek [7]4 years ago
6 0

Answer:

Mass of CaCl2 that would dissolve is 24.64g.

Explanation:

Explanation is contained in the picture attached.

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Debora [2.8K]

Answer:

chuma ya ndoshi.............

Explanation:

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kwenda ukalale .............

6 0
2 years ago
Which condition must exist in order for conduction to occur between two substances?
Sveta_85 [38]

Answer: B

Explanation:

6 0
3 years ago
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The following data were obtained in a kinetics study of the hypothetical reaction A + B + C → products. [A]0 (M) [B]0 (M) [C]0 (
Vladimir [108]

Answer:

B. First order, Order with respect to C = 1

Explanation:

The given kinetic data is as follows:

A + B + C → Products

     [A]₀     [B]₀    [C]₀       Initial Rate (10⁻³ M/s)

1.   0.4      0.4     0.2       160

2.  0.2      0.4      0.4       80

3.   0.6     0.1       0.2       15

4.   0.2     0.1       0.2        5

5.   0.2     0.2      0.4       20

The rate of the above reaction is given as:

Rate = k[A]^{x}[B]^{y}[C]^{z}

where x, y and z are the order with respect to A, B and C respectively.

k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

Order w.r.t A : Use trials 3 and 4

\frac{Rate3}{Rate4}= [\frac{[A(3)]}{[A(4)]}]^{x}

\frac{15}{5}= [\frac{[0.6]}{[0.2]}]^{x}

3 = 3^{x} \\\\x =1

Order w.r.t B : Use trials 2 and 5

\frac{Rate2}{Rate5}= [\frac{[B(2)]}{[B(5)]}]^{y}

\frac{80}{20}= [\frac{[0.4]}{[0.2]}]^{y}

4 = 2^{y} \\\\y =2

Order w.r.t C : Use trials 1 and 2

\frac{Rate1}{Rate2}= [\frac{[A(1)]}{[A(2)]}]^{x}[\frac{[B(1)]}{[B(2)]}]^{y}[\frac{[C(1)]}{[C(2)]}]^{z}

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

\frac{160}{80}= [\frac{[0.4]}{[0.2]}]^{1}[\frac{[0.4]}{[0.4]}]^{2}[\frac{[0.2]}{[0.4]}]^{z}

1 = (0.5)^{z}

z = 1

Therefore, order w.r.t C = 1

8 0
4 years ago
If you burn 28.2g of hydrogen and produce 252g of water, how much oxygen reacted
andrey2020 [161]
15% oxygen is reacted
6 0
3 years ago
(IMAGE ATTACHED)<br>(pls help this is due tonight)<br>​
miv72 [106K]

Answer:

You can see that the line is going up and is curved in a positive direction.

Explanation:

When an object is speeding up, the acceleration is in the same direction as the velocity. Thus, this object has a positive acceleration.

5 0
3 years ago
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