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Temka [501]
3 years ago
12

What is the magnitude of force required to accelerate a car

Mathematics
2 answers:
Drupady [299]3 years ago
7 0

Answer:

8.71 x 10^3N - C

Step-by-step explanation:

Force = mass x acceleration

mass = 1.7 x 10^3 and acceleration = 4.75m/s^2

Force = 1.7 x 10^3 x 4.75 = 8075N = 8.71 x 10^3N

TEA [102]3 years ago
7 0

Answer:

8,075N

Step-by-step explanation:

The information we have is:

Mass:

m=1.7x10^3kg

Acceleration:

a=4.75m/s^2

We are asked to find the force that is necessary to create that acceleration in the given mass.

For this we use the equation of Newton's second law:

F=ma

and now we susbtitute all the values into the equation to find the force F:

F=(1.7x10^3kg)(4.75m/s^2)\\F=8,075N

The magnitude of the force required is 8,075N

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Driving on the highway, you can safely drive 60 miles per hour. "How far can you drive in ‘h' hours?" What is the range of the f
JulijaS [17]

Answer:

D.The distance you drive

Step-by-step explanation:

If you describe this situation as function, then it will look as:

  • f(h)= 60h
  • For h=1 you have f(1)= 60 miles
  • For h=2 you have f(2)= 120 miles etc.

The range of the function is the set of output values

In this case the range is the distance you drive

Correct option is D.

7 0
3 years ago
Question is in the picture and answer
dmitriy555 [2]

Answer:

The correct answer is D) y + 1 = -2(x - 5)

Step-by-step explanation:

All equations can be written in the following point-slope form.

y - y1 = m(x - x1)

In which, m is the slope. (x1, y1) is the given point. If we use the information given we can find the equation.

y - - 1 = -2(x - 5)

y + 1 = -2(x - 5)

8 0
3 years ago
If two pyramids are similar and the ratio between the lengths of their edges is
SVEN [57.7K]

Answer:

D. 27:1331

Step-by-step explanation:

The volume ratio for the two solids is the side length ratio raised to the third power.

3 to the 3rd power = 27

11 to the 3rd power = 1331

5 0
3 years ago
A force of 10 lb is required to hold a spring stretched 4 in. beyond its natural length. How much work is done in stretching it
Troyanec [42]

Answer:

W = 15/4 ft . ib

Step-by-step explanation:

Force = 10ib

According to hooked law, f(x) = kx

x = 4inches = 4/12 ft

x= 1/3ft

f(x) = 1/3k

10 = 1/3k

k = 30 ib/ft

f(x) = 30x

Workdone = integral of f(x) with its limit

6 inches = 6/12 ft

= 1/2ft

W = integral(1/2 to 0) of 30x

W = 15x^2(1/2 to 0)

W = 15(1/2)^2 - 15(0)^2

W = 15(1/4) - 0

W = 15/4 ft. Ib

4 0
3 years ago
-2x - y =0 is it direct variation?​
oksian1 [2.3K]

Answer:

y=11

Step-by-step explanation:

4 0
2 years ago
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