V= s^3
a=486/6=81
s=sqrt(81)=9
v=9^3=729
the volume of the cube is 729cm^3
Answer:
81.86%
Step-by-step explanation:
We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.
First of all we will find z-score using z-score formula.
Now let us find z-score for 86.
Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.
Using normal distribution table we will get,

We will use formula
to find the probability to find that a normal variable lies between two values.
Upon substituting our given values in above formula we will get,


Upon converting 0.81859 to percentage we will get

Therefore, 81.86% of final exam score will be between 68 and 86.
Total: 160, Left:100 Right:60
10(6+2z)+8 distribute 10
60+20z+8 add like terms
68+20z is answer since you can’t simplify anything further