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aalyn [17]
3 years ago
5

Y’all answer as many as u can they just need to be correct thx!!!!

Chemistry
1 answer:
Slav-nsk [51]3 years ago
4 0

Answer:

10. Embryology is the branch of biology and medicine concerned with the study of embryos and their development.

11. I think the answer is, Both humans and whale embryos have a tail and a backbone (I'm not sure).

12. Basilosaurid, any member of the family Basilosauridae, an early group of whales that lived from the middle Eocene to the late Oligocene Epoch (about 41 million to 23 million years ago).

13.  Protocetids had long snouts, large eyes, and their nasal opening was farther caudally than in earlier archaeocetes.

14. Two ways we know that Maiacetus was a whale re:

1) Their skeletons have all been found among fossils of sea-creatures which suggests they lived in the sea.

2) Their hip bones were strong enough to walk on land, but their short legs combined with long flat fingers and toes suggest they would have had difficulty walking.

15. The name Maiacetus means Mother Whale. Maiacetus is significant because of how well the skeletons were preserved.

Hope this helps! :D

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kotykmax [81]
The correct answer is A
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3 years ago
Consider the following reaction between calcium oxide and carbon dioxide: CaO(s)+CO2(g)→CaCO3(s) A chemist allows 14.4 g of CaO
sweet-ann [11.9K]

Answer:

Theoretical yield =26.03 g

Percent yield = 87%

Limiting reactant = CaO

Explanation:

Given data:

Mass of CaO = 14.4 g

Mass of CO₂ = 13.8 g

Actual yield of CaCO₃ = 22.6 g

Theoretical yield = ?

Percent yield = ?

Limiting reactant = ?

Solution:

Chemical equation:

CaO + CO₂   → CaCO₃

Number of moles of CaO:

Number of moles  = Mass /molar mass

Number of moles = 14.4 g / 56.1 g/mol

Number of moles  = 0.26 mol

Number of moles of CO₂:

Number of moles = Mass /molar mass

Number of moles = 13.8 g / 44 g/mol

Number of moles = 0.31 mol

Now we will compare the moles of CO₂ and CaO with CaCO₃ .

                  CO₂         :                CaCO₃  

                  1               :                 1

                 0.31           :              0.31

                CaO           :               CaCO₃  

                 1                :                 1

                 0.26         :              0.26

The number of moles of  CaCO₃ produced by CaO are less it will be limiting reactant.

Mass of CaCO₃: Theoretical yield

Mass of CaCO₃ = moles × molar mass

Mass of CaCO₃ =0.26 mol × 100.1 g/mol

Mass of CaCO₃ =  26.03 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 22.6 g/ 26.03 g × 100

Percent yield = 0.87× 100

Percent yield = 87%

Limiting reactant:

The number of moles of  CaCO₃ produced by CaO are less it will be limiting reactant.

7 0
4 years ago
Mention at least two organic compounds synthesized from inorganic substanc​
Salsk061 [2.6K]

Answer:

p-Nitro acetanilide. 2-Naphthol aniline dye.

8 0
3 years ago
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