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4 years ago

6

What will happen if you add more solute to a saturated solution?

1 answer:

Annette [7]4 years ago

4 0

No more solute will dissolve at that temperature, the temperature would have to be increased in order for more solute to dissolve.

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A sample of nitrogen gas has a volume of 237mL at 9.86atm. What is the new

MrRa [10]

Answer:

The new volume of the gas when the pressure is changed to 2.84 atm is 822.82 mL.

Explanation:

Boyle's law says that "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." That is, if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

or

P * V = k

Assuming that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:

P1*V1= P2*V2

In this case:

P1= 9.86 atm
V1= 237 mL
P2= 2.84 atm
V2=?

Replacing:

9.86 atm* 237 mL= 2.84 atm*V2

and solving you get:

$V2=\frac{9.86 atm* 237 mL}{2.84 atm}$

V2= 822.82 mL

<u><em>The new volume of the gas when the pressure is changed to 2.84 atm is 822.82 mL.</em></u>

3 0

3 years ago

The number of total electrons of iron is:<br> a) 55.85<br> b)29.85<br> c)26<br> d)27.78<br> e) 56

AleksandrR [38]

I think the answer is b

6 0

3 years ago

Read 2 more answers

Which of the following is the most likely impact of clearing natural landscape to construct high-rise buildings?

Salsk061 [2.6K]

Answer:

the abundance of non-native plants. this MAY be right.

Explanation:

i thought it would be an increase in pollution.

7 0

2 years ago

Consider the reaction: A (aq) ⇌ B (aq) at 253 K where the initial concentration of A = 1.00 M and the initial concentration of B

Ugo [173]

Answer:

The maximum amount of work that can be done by this system is -2.71 kJ/mol

Explanation:

Maximum amount of work denoted change in gibbs free energy $(\Delta G)$ during the reaction.

Equilibrium concentration of B = 0.357 M

So equilibrium concentration of A = (1-0.357) M = 0.643 M

So equilibrium constant at 253 K, $K_{eq}= \frac{[B]}{[A]}$

[A] and [B] represent equilibrium concentrations

$K_{eq}=\frac{0.357}{0.643}=0.555$

When concentration of A = 0.867 M then B = (1-0.867) M = 0.133 M

So reaction quotient at this situation, $Q=\frac{0.133}{0.867}=0.153$

We know, $\Delta G=RTln(\frac{Q}{K_{eq}})$

where R is gas constant and T is temperature in kelvin

Here R is 8.314 J/(mol.K), T is 253 K, Q is 0.153 and $K_{eq}$ is 0.555

So, $\Delta G=8.314\times 253\times ln(\frac{0.153}{0.555})mol/K$

= -2710 J/mol

= -2.71 kJ/mol

4 0

3 years ago

Someone help me please i’ll give brainly

Nitella [24]

Answer:

solid

liquid

Gas

plasma

4 0

3 years ago

Read 2 more answers