Question

write the slope-intercept form for the equation of the line described through (4,-5) and parallel to y=--5/4x-4

Answer 1

Answer:

y = -5x/4 + 0

Step-by-step explanation:

Find the slope

y = -5/4x - 4

Slope is the coefficient of x

Slope m = -5/4

Substitute m into point slope form equation

y - y1 = m(x - x1)

y - y1 = -5/4( x - x1)

Substitute the point into the equation

( 4 , -5)

x1 = 4

y1 = -5

y - y1 = -5/4( x - x1)

y - (-5) = -5/4( x - 4)

y + 5 = -5/4(x - 4)

Using a slope intercept form equation

y = mx + c

y - intercept point y

m - slope

x - intercept point x

c - intercept

open the bracket with -5/4

y + 5 = -5(x - 4)/4

y + 5 = (-5x + 20)/4

y = (-5x + 20)/4 - 5

LCM = 4

y =( -5x + 20 - 20)/4

y = ( -5x + 0)/4

Rearrange in

y = mx + c

y = -5x/ 4 + 0/4

y = -5x/4 + 0

The equation of the line is

y = -5x/4 + 0