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oksian1 [2.3K]
3 years ago
9

In a chemical equation what name does the left side have

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
4 0
A chemical equation is a short hand expression of a chemical reaction. There aretwo<span> parts to a chemical equation. The reactants are the elements or compounds on the left side of the arrow (-->). The elements and compounds to the right of the arrow are the products.</span>
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The primary role of the carbonic-acid-bicarbonate buffer system is to
tekilochka [14]

Answer:

The primary role of the carbonic-acid-bicarbonate buffer system is to neutralize the hydronium ions forming carbonic acid and water when any acidic substance enter the bloodstream.

Explanation:

hope it helps.

4 0
3 years ago
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:
cupoosta [38]
MgO
MgI2
PbO2
PbI4

These are the possible compounds
4 0
3 years ago
Read 2 more answers
A 0.533 g sample of a carbonate salt is added to a flask. The only thing you know is that per formula unit, there is only one ca
dimulka [17.4K]

Answer:

\mathbf{CrCO_3}

Explanation:

The total mole of H_2SO_4 added = 15 × 1 × 10⁻³

= 15 × 10⁻³ mole

= 15 mmoles

the number of moles of NaOH added in order to neutralize the excess acid = 0.5905 ×  29.393 = 17.36 mmoles

the equation for the reaction is:

2NaOH + H_2SO_4 --------> Na_2SO_4 +2H_2O

i.e

2 moles of NaOH react with H_2SO_4

1 moles of  NaOH will react with 1/2  H_2SO_4

17.36 mmoles of NaOH = 1/2 × 17.36 mmoles of H_2SO_4

                                       = 8.68 mmoles

Number of moles of H_2SO_4 that react with MCO₃ = Total moles of H_2SO_4 added - moles of H_2SO_4 reacted with NaOH

= (15 - 8.68) mmoles

= 6.32 mmoles

H_2SO_4 + MCO_3  ------>   M_2SO_4   +    H_2O   +   CO_2

1 mole of H_2SO_4 react with 1 mole of MCO_3

6.32 mmoles of H_2SO_4 = 6.32 mmoles of MCO_3

number of moles of MCO_3 = 6.32 10⁻³ moles

mass of  MCO_3 (carbonate salt) = 0.533 g

molar mass of MCO_3  = (M+60)g/mol

We all know that ;

number of moles = mass/molar mass

Then:

6.32 10⁻³ = 0.533 / (M+60)

(M+60) = 0.533/ 6.32 10⁻³

M + 60 = 84.34

M = 84.34 - 60

M = 24.34

Thus the element with the atomic mass of 24.34 is Chromium

The chemical formula for the compound is :  \mathbf{CrCO_3}

6 0
3 years ago
Use the correct terms to explain the osmotic concentrations of the solutions.
Morgarella [4.7K]
The movement of water from lower concentration to higher concentration trough semipermeable membrane.
3 0
3 years ago
Calculate the number of moles 3.16 g of KMnO4 32.33 g of K2CrO4 100 g of KHCO3
kvasek [131]
The number of moles:
3.16g of KMnO_{4}
1 mole of KMnO_{4}- 158g.
x moles of KMnO_{4}- 3.16g.
x=\frac{1\ mole*3.16g}{158g}=\frac{3.16}{158}=0.02\ mole

The number of moles:
32.33g of K_{2}CrO_{4}
1 mole of K_{2}CrO_{4}- 194g.
x moles of K_{2}CrO_{4}- 32.33g.
x=\frac{1\ mole*32.33g}{194g}=\frac{32.33}{194}=0.17\ mole

The number of moles:
100g of KHCO_{3}
1 mole of KHCO_{3}- 100.1g.
x moles of KHCO_{3}- 100g.
x=\frac{1\ mole*100g}{100.1g}=\frac{100}{100.1}=0.999\ mole


Greetings, 
n00nst00p :)
3 0
2 years ago
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