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tatyana61 [14]
2 years ago
13

Calculate the number of moles 3.16 g of KMnO4 32.33 g of K2CrO4 100 g of KHCO3

Chemistry
1 answer:
kvasek [131]2 years ago
3 0
The number of moles:
3.16g of KMnO_{4}
1 mole of KMnO_{4}- 158g.
x moles of KMnO_{4}- 3.16g.
x=\frac{1\ mole*3.16g}{158g}=\frac{3.16}{158}=0.02\ mole

The number of moles:
32.33g of K_{2}CrO_{4}
1 mole of K_{2}CrO_{4}- 194g.
x moles of K_{2}CrO_{4}- 32.33g.
x=\frac{1\ mole*32.33g}{194g}=\frac{32.33}{194}=0.17\ mole

The number of moles:
100g of KHCO_{3}
1 mole of KHCO_{3}- 100.1g.
x moles of KHCO_{3}- 100g.
x=\frac{1\ mole*100g}{100.1g}=\frac{100}{100.1}=0.999\ mole


Greetings, 
n00nst00p :)
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