Answer:
Proton, neutron, electron
Explanation:
The atom consists of a nucleus, where almost all the mass is concentrated, and electrons orbiting around the nucleus.
The nucleus consists of two types of particles:
- Proton: it has a mass of
, and a positive electric charge of +e (
)
- Neutron: it has a mass of
, and it has no electric charge
The third particle that makes an atom is the electron, that orbit around the nucleus:
- Electron: it has a mass of
, and it has a negative electric charge of -e (
)
Answer:
63.750KeV
Explanation:
We are given that
Initial velocity of second electron,
Radius,

1 m=100 cm
Magnetic field,B=0.0370 T
We have to determine the energy of the incident electron.
Mass of electron,
Charge on an electron,
Velocity,
Using the formula
Speed of electron,
Speed of second electron,

Kinetic energy of incident electron=
Kinetic energy of incident electron=
Kinetic energy of incident electron=
1KeV=1000eV
Answer:
A molecule is something every mass has and is very small
Explanation:
Answer:
Pressure will be 
Explanation:
We have given mass of the women m = 65 kg
Radius of the heels r = 0.578 cm = 0.00578 m
We have to find the pressure
We know that pressure is given by

So force F = mg = 65×9.8 = 637 N
Area 
So pressure 
Answer:
The handrails must be approximately 10.63 meters long
Explanation:
The given parameters are;
The height of the bleachers, h = 8 m
The depth of the bleachers, d = 7 m
The length of the hand rails to go along the bleachers from bottom to top is given by Pythagoras' Theorem as follows;
The length of the hand rail = √(d² + h²)
∴ The length of the hand rail = √(7² + 8²) = √113 ≈ 10.63
In order for the handrails to go along the bleachers from top to bottom, they must be approximately 10.63 meters long.