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3 years ago

Each lunar cycle has one full moon, in which the relative positions of Earth, the sun, and the moon form in a straight line

Physics

1 answer:

aniked [119]3 years ago

3 0

Complete Question:

Each lunar cycle has one full moon, in which the relative positions of Earth, the sun, and the moon form in a straight line. Which list represents the position of Earth, the sun, and the moon during a full moon?

Group of answer choices.

A. Earth, sun, moon

B. sun, moon, Earth

C. moon, sun, Earth

D. sun, Earth, moon

Answer:

D. sun, Earth, moon

Explanation:

A lunar eclipse is a phenomenon that occurs when the Earth comes between the Moon and the Sun thereby causing it to cover the Moon with its shadow.

Simply stated, lunar eclipse takes place when the Moon passes or moves through the Earth's shadow thereby blocking any ray of sunlight from reaching the Moon. Thus, the full moon appears deep red (blood moon).

Also, a lunar eclipse would occur only when the Sun, Earth, and Moon are closely aligned to form a straight line known as the syzygy.

There are three (3) types of lunar eclipse and these are;

1. Total lunar eclipse.

2. Partial lunar eclipse.

3. Penumbra lunar eclipse.

Each lunar cycle has one full moon, in which the relative positions of Earth, the sun, and the moon form in a straight line. Thus, the list which represents the position of Earth, the sun, and the moon during a full moon is sun, Earth, and moon

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A car battery with a 12 V emf and an internal resistance of 0.037 Ω is being charged with a current of 45 A. Note that in this p

matrenka [14]

Answer:

Part a)

$V = 13.665 V$

Part b)

$P = 74.9 Watt$

Part c)

$P = 540 watt$

Part d)

$P_r = 0.878$

Explanation:

Part a)

As we know that the during the charging process of the battery the terminal voltage of the cell is given as

$V = E + iR$

$V = 12 + (0.037)(45)$

$V = 13.665 V$

Part b)

Thermal energy dissipated in the battery is due to its internal resistance

so it is given as

$P = i^2 R$

here we have

$P = 45^2 (0.037)$

$P = 74.9 Watt$

Part c)

rate of energy conversion in the in the battery is given as

$P = E. i$

$P = 12(45)$

$P = 540 watt$

Part d)

percentage of the power conversion is given as

$Pr = \frac{P_{out}}{P_{total}}$

$Pr = \frac{540}{540 + 74.9}$

$P_r = 0.878$

6 0

3 years ago

Find the intensity of a 55 dB sound given lo-10-12 wm2

Inessa05 [86]

Answer:

Intensity= $I=3.16\times 10^{-7}\ W\ m^{-2}$

Explanation:

Given:

$\beta=55\ dB\\I_o=10^{-12}\ W\ m^{-2}$

The sound level $\beta$ in dB with intensity $I$

and reference intensity $I_0$ is given by:

$\beta(dB)=10 \log_{10}(\frac{I}{I_0})$

Plugging in values.

$55=10 \log_{10}(\frac{I}{10^{-12}})$

Dividing both sides by 10.

$\frac{55}{10}=\frac{10 \log_{10}(\frac{I}{10^{-12}})}{10}$

$5.5=\log_{10}\frac{I}{10^{-12}}$

The above can be written as

$10^{5.5}=\frac{I}{10^{-12}}$

Multiplying both sides by $10^{-12}$

$10^{5.5}\times 10^{-12}=10^{-12}\times \frac{I}{10^{-12}}$

$10^{(5.5-12)}=I$

$10^{(-7.5)}=I$

∴ $I=3.16\times 10^{-7}\ W\ m^{-2}$

Intensity = $I=3.16\times 10^{-7}\ W\ m^{-2}$

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3 years ago

Consider an electron that is 100 m from an alpha particle ( = 3.2 x 10-19 C). (Enter the magnitudes.) (a) What is the electric f

scoundrel [369]

Answer:

a) $E=2.88*10^{-13}N/C$

b) $E=1.44*10^{-13}N/C$

c) $F=4.61*10^{-32}N$

Explanation:

The definition of a electric field produced by a point charge is:

$E=k*q/r^2$

a)Electric Field due to the alpha particle:

$E=k*q_{alpha}/r^2=9*10^9*3.2*10^{-19}/(100)^2=2.88*10^{-13}N/C$

b)Electric Field due to the electron:

$E=k*q_{electron}/r^2=9*10^9*1.6*10^{-19}/(100})^2=1.44*10^{-13}N/C$

c)Electric Force on the alpha particle, on the electron:

The alpha particle and electron feel the same force magnitude but with opposite direction:

$F=k*q_{electron}*q_{alpha}/r^2=9*10^9*1.6*10^{-19}*3.2*10^{-19}/(100)^2=4.61*10^{-32}N$

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3 years ago

What is first and second conditions of equilibrium?

sdas [7]

I think the answer is the first condition sum of forces acting on a body is zero ( ∑ F =0 ) and the second condition sum of torque acting on a body is ( ∑ τ = 0 )

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2 years ago

A system has two possible energy states, E0 and E1 (with E1 > E0). If the difference between these energy states grows (E0 an

Ugo [173]

Answer:

The number of particles in state E0 over the number of particles in state E1 will reduce

Explanation:

E0 represents the ground level state when all the particles have same energy level.

E1 represents excited state in which only a few particle reaches

E0 and E1 get further apart means that the energy difference between the two level increases.

Thus, the number of particles in state E0 over the number of particles in state E1 will reduce.

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3 years ago