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fomenos
3 years ago
14

Two electric charges, held a distance, dd, apart experience an electric force of magnitude, FF, between them. If one of the char

ges is doubled in magnitude while maintaining the same separation between the charges, what is the new magnitude of the force between them?
Physics
1 answer:
lorasvet [3.4K]3 years ago
3 0

Answer:

F'=2F

Explanation:

The Coulomb's law states that the magnitude of the electrostatic force between two charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them:

F=\frac{kq_1q_2}{d^2}

In this case, we have q_1'=2q_1:

F'=\frac{kq'_1q_2}{d^2}\\F'=\frac{k(2q_1)q_2}{d^2}\\F'=2\frac{kq_1q_2}{d^2}\\F'=2F

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You illuminate the surface of some metal with green laser and observe the photocurrent. If you decrease the intensity of laser,
gregori [183]

Remain the same.

Explanation:

The kinetic energy of the ejected electrons, and thus the resulting photocurrent, does not depend on the intensity of the incident radiation. Instead, it depends on the frequency. So since the stopping potential is used to reduce the photocurrent to zero and the photocurrent does not depend on the intensity, the stopping potential remains the same.

7 0
2 years ago
A cylinder with a movable piston contains a sample of ideal gas. A temperature probe and a pressure probe are inserted into the
PtichkaEL [24]

Answer:

i. The values for the graph are;

Volume Pressure

1                  1

1/4               1

1                   1/4

1                   1

The graph is attached

ii. Energy is added to the system.

Explanation:

i) Here we note that Charles law states that the volume of a given mass of gas is directly proportional to its temperature at constant pressure.

Therefore;

T₁/V₁ = T₂/V₂

Where V₂ = V₁/4, we have;

T₁/V₁ = T₂/(V₁/4) = 4×T₂/V₁

T₁ =  4×T₂

Therefore, T₂ = T₁ /4

In process BC, whereby the gas expands isothermally to original volume, we have; according to Boyle's law

P₁·V₁  = P₂·V₂

V₁ = 4·V₂

∴ P₁·4·V₂  = P₂·V₂

4·P₁  = P₂

Process CA, gas returns to initial state with T₂ = T₁ /4

Therefore, we have from Pₐ·Vₐ/Tₐ = P₁·V₁/T₁

Where the volume remain constant, we have Gay Lussac's Law which states that the pressure of a given mass of gas is directly proportional to its temperature, therefore

P₁/T₁ = P₂/T₂

Hence; whereby the temperature changes from T₂ to T₁ and T₂ = T₁ /4, we have P₁ = 4·P₂

Therefore, the pressure increases by a factor of 4 × 4 = 16.

Please find the graph attached

ii) Given that the gas expands to its original volume V₁, such that V₁ = 4·V₂, also work done, W is given as follows;

W = nRTln\frac{v_f}{v_i} = nRTln\frac{v_1}{v_2} \ \because  v_f =v_1 \ and \ v_i = v_2 \ also \ v_1 = 4\cdot v_2

Therefore;

W = nRTln\frac{4\cdot v_2}{v_2} \ \therefore W = nRTln(4)

Hence, as n, R, and T are all positive values, W is positive, energy is added to the system.

8 0
3 years ago
A steel beam is rotated in a horizontal plane to provide the centripetal acceleration for
oksian1 [2.3K]

Answer:

12 m/s

Explanation:

a = v² / r

78 m/s² = v² / 2.0 m

v = 12.49 m/s

Rounding to two significant figures, the speed is 12 m/s.

7 0
3 years ago
Which of the following is an example of the law of multiple proportions?
ser-zykov [4K]

The answer option which is an example of the law of multiple proportions is: B) Two different compounds formed from carbon and oxygen have the following mass ratios: 1.33 g O: 1 g C and 2.66 g O: 1 g C.

The Law of Multiple Proportions is also referred to as Dalton's Law and it states that when two chemical elements combine to form more than one chemical compound, the masses (weights) of one chemical element that combine with a fixed mass (weight) of the other chemical element will always be in a ratio of small whole numbers.

According to the Law of Multiple Proportions, when two chemical elements combine to form two different chemical compound, the masses (weights) of one chemical element that combine with 1 gram of the other chemical element can be expressed as a ratio of small whole numbers.

For example, carbon and oxygen react to form either carbon monoxide and carbon dioxide.

<u>Carbon monoxide (CO):</u>

12 grams of C = 16 grams of O.

1 gram of C = 1.33 gram of O.

<u>Carbon dioxide (</u>CO_2<u>):</u>

12 gram of C = 32 grams of O.

1 gram of C = 2.66 gram of O.

Ratio of oxygen (O) = 16:32 = 1:2 (Law of Multiple Proportions).

Read more: brainly.com/question/21280037

Your question is lacking the necessary answer options, so I will be adding them here:

A. A sample of chlorine is found to contain three times as much Cl-35 as Cl-37.

B. Two different compounds formed from carbon and oxygen have the following mass ratios: 1.33 g O: 1 g C and 2.66 g O: 1 g C.

C. Two different samples of table salt are found to have the same ratio of sodium to chlorine.

D. The atomic mass of bromine is found to be 79.90 amu.

E. Nitrogen dioxide always has a mass ratio of 2.28 g O: 1 g N.

3 0
2 years ago
Convert 0.0779 kg to g
Mariana [72]
I think it would be 77.9 grams
5 0
3 years ago
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