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2 years ago

What is the net force acting on an object that is not accelerating in the horizontal axis?

Physics

1 answer:

yuradex [85]2 years ago

8 0

Answer:

.......................

Explanation:

A net force = unbalanced force. If however, the forces are balanced (in equilibrium) and there is no net force, the object will not accelerate and the velocity will remain constant.

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Water enters a shower head

zalisa [80]

Answer:

13.1

Explanation:

thats what i put in for acellus and its right

4 0

3 years ago

Which statement best describes the atoms of elements that form compounds by covalent bonding?

k0ka [10]

Answer:

they share electrons between them.

Explanation:

taking the test rn lol i think its right

4 0

3 years ago

The temperature of a black body is 500 and its radiation is of wavelength 600 . If the number of oscillators with energy is 100

stiks02 [169]

Answer: An equation is missing in your question below is the missing equation

a) ≈ 8396

b) 150 nm/k

Explanation:

A) Determine the number of Oscillators in the black body

number of oscillators = 8395

attached below is the detailed solution

b) determine the peak wavelength of the black body

Black body temperature = 20,000 K

applying Wien's law / formula

λmax = b / T ------ ( 1 )

T = 20,000 K

b = 3 * 10^6 nm

∴ λmax = 150 nm/k

4 0

3 years ago

Identify the vibrating media in three different types of musical instruments.

mart [117]

Explanation:

Hole. Hole. Different notes can be played on the flute by blocking holes. ...

Drum skin. Drum skin. Hitting the bongo drum makes its tight elastic skin vibrate.

String. String. ...

Sound. hole. ...

Bow. Bow.

3 0

3 years ago

Three long parallel wires each carry 2.0-A currents in the same direction. The wires are oriented vertically, and they pass thro

blagie [28]

Answer:

$21.2\times 10^{-6}$ T

Explanation:

$i$ = magnitude of current in each wire = 2.0 A

$a$ = length of the side of the square = 4 cm = 0.04 m

$r$ = length of the diagonal of the square = $\sqrt{2}$ a = $\sqrt{2}$ (0.04) = 0.057 m

$B$ = magnitude of magnetic field by wires at A and C

$B = \left ( \frac{\mu _{o}}{4\pi } \right )\left ( \frac{2i}{a} \right )$

$B = (10^{-7}) \left ( \frac{2(2)}{0.04} \right )$

$B = 10\times 10^{-6}$ T

$B'$ = magnitude of magnetic field by wire at B

$B' = \left ( \frac{\mu _{o}}{4\pi } \right )\left ( \frac{2i}{r} \right )$

$B' = (10^{-7}) \left ( \frac{2(2)}{0.057} \right )$

$B' = 7.02\times 10^{-6}$ T

Net magnitude of the magnetic field at D is given as

$B_{net} = \sqrt{B^{2}+B^{2}} + B'$

$B_{net} = \sqrt{2} B + B'$

$B_{net} = \sqrt{2} (10\times 10^{-6}) + (7.02\times 10^{-6})$

$B_{net} = 21.2\times 10^{-6}$ T

8 0

3 years ago