Answer:
The vulture loses 6.1 m height
Explanation:
Please see the attached figure.
The horizontal distance and the loss of height form a 90º triangle.
The loss of height is the side opposite the given angle (3.5º) and the 100 m horizontal distance is adjacent the angle.
Then, using trigonometric rules:
(1) sin 3.5º = h / hyp
(2) cos 3.5º = distance / hyp
where
h = height lost during the flight.
hyp = hypotenuse of the triangle
Using (2) we can calculate the hypotenuse:
cos 3.5º = 100 m / hyp
hyp = 100 m / cos 3.5º = 100.2 m
with the hypotenuse we can now calculate the loss of height using (1):
sin 3.5º = h / hyp
sin 3.5º = h / 100.2 m
sin 3.5º * 100.2 m = h
<u>h = 6.1 m</u>
( very modest drop in height indeed!)
Explanation:
Below is an attachment containing the solution.
Missing figure in the problem: https://www.physicsforums.com/attachments/p4-46-gif.117834/
Solution:
part a) The bucket is not moving so the resultant of the forces acting on it is zero. Let's apply the equation of equilibrium. We have:

so

where T=90.5 N is the tension of the rope, and a factor 2 is applied because the string holds the bucket twice. From this we find

part b) Here the situation is different: the string holds the bucket only in one point. Moreover, the bucket is pulled up at constant velocity, so zero acceleration: this means that the resultant of the forces acting on the bucket is zero. Therefore, the equation of equilibrium in this case is

and so, since we know from part a) that

, we can find the new tension T:
To put it another way, stationary states are the same as time-independent currents. Moreover, such currents are not sources of radiation, according to Maxwell's theory. The atom will remain in its natural state and will not collapse due to a shortage of energy.
Answer:
a) Kinetic energies
K₁ = 1.2 J
K₂ = 7.5 J
b) The bullet that has the highest kinetic energy is the one with the highest speed , v = 50 m/s , K₂ = 7.5 J
c) K₂ -K₁ = 6.3 J
Explanation:
The kinetic energy (K) is that due to the movement of a body and is calculated as follows:
K = (1/2) m*v² (J)
Where :
m : the mass of the body ( kg)
v is the speed of the body (m/s)
Data
m₁ = m₂ = 0.006 Kg
v₁ = 20 m/s
v₂ = 50 m/s
a)Calculation of the kinetic energy
K₁ = (1/2) (m₁)*(v₁)²
K₁ = (1/2) (0.006)*(20)²
K₁ = 1.2 J
K₂= (1/2) (m₂)*(v₂)²
K₂ = (1/2) (0.006)*(50)²
K₂ = 7.5 J
b) K₂ ˃ K₁
The bullet that has the highest kinetic energy is the one with the highest speed , v = 50 m/s, K₂ = 7.5 J
c) Difference of their kinetic energies (K₂ -K₁)
K₂ -K₁ = 7.5 J - 1.2 J = 6,3 J