All categories

3 years ago

PLS HELP

Chemistry

1 answer:

aivan3 [116]3 years ago

6 0

Answer:

Percent yield of silver obtained = 78.18% (Approx.)

Explanation:

Given:

Amount of copper = 50 gram

Amount of silver nitrate = 300 gram

Amount of silver = 149 gram

Find:

Percent yield of silver obtained

Computation:

Percentage of Silver in silver nitrate = 108[100/(108+14+48)]

Percentage of Silver in silver nitrate = 108/[100/170]

Percentage of Silver in silver nitrate = 63.53% (Approx.)

Amount of Silver produced = [63.53%][300]

Amount of Silver produced = 190.59 gram

Percent yield of silver obtained = [Amount of silver / Amount of silver produced]100

Percent yield of silver obtained = [149/190.59]100

Percent yield of silver obtained = 78.18% (Approx.)

You might be interested in

Help me with these questions :)

maxonik [38]

Answer:

1 ) H2O 2) Hydrogen and oxygen 3) Compound

Explanation:

1) To write a chemical formula, you write the number of molecules of an element (2 hydrogen atoms + 1 Oxygen atom, or H2O). The letters represent the element's notation on the periodic table, while the number that follows it represents the number of atoms of that particular element within the compound. If there is no number that follows the letter, there is only one.

2) Letter "H" on the periodic table represents hydrogen, while "O" represents oxygen

3) You can tell that this is a compound because it is made of two or more elements found on the periodic table

3 0

3 years ago

A chemical reaction produces 3.81g potassium chloride (KCl). How many formula units of potassium chloride are there? *Find Molar

Aleks04 [339]

Answer:

The number of formula units in 3.81 g of potassium chloride (KCl) is approximately 3.08 × 10²²

Explanation:

The given parameters is as follows;

The mass of potassium chloride produced in the chemical reaction (KCl) = 3.81 g

The required information = The number of formula units of potassium chloride (KCl)

The Molar Mass of KCl = 74.5513 g/mol

$The \ number \ of \ moles \ of \ a \ substance, n = \dfrac{The \ mass \ of \ the substance}{The \ Molar \ Mass \ of \ the \ substance}$

Therefore, we have;

$The \ number \ of \ moles \ of \ KCl= \dfrac{3.81 \ g}{74.5513 \ g/mol} \approx 0.051106 \ moles$

1 mole of a substance, contains Avogadro's number (6.022 × 10²³) of formula units

Therefore;

0.051106 moles of KCl contains 0.051106 × 6.022 × 10²³ ≈ 3.077588 × 10²² formula units

From which we have, the number of formula units in 3.81 g of potassium chloride (KCl) ≈ 3.08 × 10²² formula units.

8 0

3 years ago

IUPAC NAME FOR:<br>CH2(OH)-CH2-CH(C2H5)-OH

fgiga [73]

The IUPAC name for the organic compound CH2(OH)-CH2-CH(C2H5)-OH is Pentan-1,3-diol

This compound above belong to class of organic compound called the alkanols

<h3>What are organic compounds?</h3>

Organic compounds are compounds which contains carbon and hydrogen only.

Some few classes of organic compounds includes the following:

Alkanes
Alkenes
Alkynes
Alkanols
Alkanals
Alkanones
Esters
Ketones and other

So therefore, the IUPAC name for the organic compound is CH2(OH)-CH2-CH(C2H5)-OH is Pentan-1,3-diol

Learn more about organic compounds:

brainly.com/question/704297

#SPJ1

6 0

2 years ago

What volume of water is required to prepare 0.1 M H3PO4 from 100 ml of 0.5 M solution?

ExtremeBDS [4]

Answer: A volume of 500 mL water is required to prepare 0.1 M $H_{3}PO_{4}$ from 100 ml of 0.5 M solution.

Explanation:

Given: $M_{1}$ = 0.1 M, $V_{1}$ = ?

$M_{2}$ = 0.5 M, $V_{2}$ = 100 mL

Formula used to calculate the volume of water is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times V_{1} = 0.5 M \times 100 mL\\V_{1} = 500 mL$

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M $H_{3}PO_{4}$ from 100 ml of 0.5 M solution.

7 0

3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Trava [24]

Answer:

b..................

4 0

3 years ago

Read 2 more answers