PLS HELP

Chemistry

1 answer:

aivan3 [116]2 years ago

6 0

Answer:

Percent yield of silver obtained = 78.18% (Approx.)

Explanation:

Given:

Amount of copper = 50 gram

Amount of silver nitrate = 300 gram

Amount of silver = 149 gram

Find:

Percent yield of silver obtained

Computation:

Percentage of Silver in silver nitrate = 108[100/(108+14+48)]

Percentage of Silver in silver nitrate = 108/[100/170]

Percentage of Silver in silver nitrate = 63.53% (Approx.)

Amount of Silver produced = [63.53%][300]

Amount of Silver produced = 190.59 gram

Percent yield of silver obtained = [Amount of silver / Amount of silver produced]100

Percent yield of silver obtained = [149/190.59]100

Percent yield of silver obtained = 78.18% (Approx.)

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