The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers.
<h3>When was Einstein miracle year?</h3>
The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers in a short time and became very popular.
His mindset in that year was one that challenged the orthodox explanations and sought to think outside the box.
Learn more about Albert Einstein:brainly.com/question/2964376
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Answer:
The taken is ![t_A = 19.0 \ s](https://tex.z-dn.net/?f=t_A%20%20%3D%2019.0%20%5C%20s)
Explanation:
Frm the question we are told that
The speed of car A is ![v_A = 22 \ m/s](https://tex.z-dn.net/?f=v_A%20%20%3D%20%2022%20%5C%20m%2Fs)
The speed of car B is ![v_B = 29.0 \ m/s](https://tex.z-dn.net/?f=v_B%20%20%3D%2029.0%20%5C%20m%2Fs)
The distance of car B from A is ![d = 300 \ m](https://tex.z-dn.net/?f=d%20%3D%20300%20%5C%20m)
The acceleration of car A is ![a_A = 2.40 \ m/s^2](https://tex.z-dn.net/?f=a_A%20%20%3D%202.40%20%5C%20m%2Fs%5E2)
For A to overtake B
The distance traveled by car B = The distance traveled by car A - 300m
Now the this distance traveled by car B before it is overtaken by A is
![d = v_B * t_A](https://tex.z-dn.net/?f=d%20%3D%20v_B%20%2A%20t_A)
Where
is the time taken by car B
Now this can also be represented as using equation of motion as
![d = v_A t_A + \frac{1}{2}a_A t_A^2 - 300](https://tex.z-dn.net/?f=d%20%3D%20v_A%20t_A%20%20%2B%20%5Cfrac%7B1%7D%7B2%7Da_A%20t_A%5E2%20-%20300)
Now substituting values
![d = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300](https://tex.z-dn.net/?f=d%20%3D%2022t_A%20%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%282.40%29%5E2%20t_A%5E2%20-%20300)
Equating the both d
![v_B * t_A = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300](https://tex.z-dn.net/?f=v_B%20%2A%20t_A%20%3D%2022t_A%20%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%282.40%29%5E2%20t_A%5E2%20-%20300)
substituting values
![29 * t_A = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300](https://tex.z-dn.net/?f=29%20%2A%20t_A%20%3D%2022t_A%20%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%282.40%29%5E2%20t_A%5E2%20-%20300)
![7 t_A = \frac{1}{2} (2.40)^2 t_A^2 - 300](https://tex.z-dn.net/?f=7%20t_A%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%282.40%29%5E2%20t_A%5E2%20-%20300)
![7 t_A =1.2 t_A^2 - 300](https://tex.z-dn.net/?f=7%20t_A%20%3D1.2%20t_A%5E2%20-%20300)
![1.2 t_A^2 - 7 t_A - 300 = 0](https://tex.z-dn.net/?f=1.2%20t_A%5E2%20-%207%20t_A%20-%20300%20%20%3D%200)
Solving this using quadratic formula we have that
![t_A = 19.0 \ s](https://tex.z-dn.net/?f=t_A%20%20%3D%2019.0%20%5C%20s)
Answer:
ANSWER BELOW I
I
V
Remember that w=mg where w is weight in Newtons, m is mass in kilograms, and g is gravity in
m/s2
. For example, for Earth, 445 N = 45.4 × 9.8
m/s2
:Notice that the x-axis values will be gravity in
m/s2
, which is already given in the table, and the y-axis values will be the weight in Newtons. Remember to round your weights to a whole number, and to enter the points starting with the lowest gravity (moon, then Mars, then Venus, then Earth).
Answer:
The question is wrong Since if you apply Force on 0.0m²It would mean That the pressure exerted=F/A=F/0
An since we can't divide a number by 0, the question is wrong
A covalent bond is between two nonmetals. An ionic bond is between a metal and a nonmetal. Potassium is a metal and iodine is a nonmetal, so their bond would most likely be ionic.