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3 years ago

A television camera lens has a 17-cm focal length and a lens diameter of 6.0 cm. what is its number?

Physics

1 answer:

IRINA_888 [86]3 years ago

3 0

Answer:

= 2.83

Explanation:

F number (N) is given by the formula;

F- number = f/D

where f = focal length of lens and D = diameter of the aperture

Therefore;

F number = 17 cm/6 cm

<u> = 2.83</u>

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What happens when you compress a gas?

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The density increases.
When gases are compressed, their volume decreases, and the resulting pressure increases. The temperature will change if either P or V are held constant. Since the volume decreases, then density, or m/V, increases.
P×V ~ T

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Two pianos each sound the same note simultaneously, but they are both out of tune. On a day when the speed of sound is 349 m/s,

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Answer:

Time period between the successive beats will be 0.1703 sec

Explanation:

We have given speed of the sound v = 349 m/sec

Wavelength of piano $A\lambda _A=0.766m$

Wavelength of piano $B\lambda _B=0.776m$

So frequency of piano A $f_1=\frac{v}{\lambda _1}=\frac{349}{0.766}=455.61Hz$

Frequency of piano B $f_2=\frac{v}{\lambda _1}=\frac{349}{0.776}=449.74Hz$

So beat frequency f = 455.61 - 449.74 = 5.87 Hz

So time period $T=\frac{1}{f}=\frac{1}{5.87}=0.1703sec$

So time period between the successive beats will be 0.1703 sec

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If a persons skin is dry she will experience more of a shock

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Answer:

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You are at a train station, standing next to the train at the front of the first car. The train starts moving with constant acce

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The time needed for the 7th car to pass is 13.2 s

Explanation:

The motion of the train is a uniformly accelerated motion, therefore we can use suvat equations.

We start by analzying the motion of the first car, by using the equation:

$s=ut+\frac{1}{2}at^2$

where

s is the distance covered by the first car in a time t, which corresponds to the length of one car

u = 0 is the initial velocity

a is the acceleration

t = 5.0 s is the time

The equation can be rewritten as

$a=\frac{2s}{t^2}=\frac{2L}{(5.0)^2}=0.08L[m/s^2]$

where L is the length of one car.

The same equation can be written considering the first 7 cars:

$7L = ut+\frac{1}{2}at'^2$

where

7L is the distance covered by the 7 cars

t' is the time needed

We still have

u = 0

And the acceleration is constant so it is

$a=0.08L$

Substituting into the equation, we can find t':

$7L = \frac{1}{2}(0.08L)t'^2\\7=0.04t'^2\\t'=\sqrt{\frac{7}{0.04}}=13.2 s$

In attachment the graph of the distance covered versus the time taken: since the motion is uniformly accelerated, the relationship between the two variables is quadratical.

Learn more about accelerated motion:

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