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Olegator [25]
3 years ago
5

A television camera lens has a 17-cm focal length and a lens diameter of 6.0 cm. what is its number?

Physics
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

= 2.83

Explanation:

F number (N) is given by the formula;

  F- number = f/D

where f = focal length of lens and D = diameter of the aperture  

Therefore;

F number = 17 cm/6 cm

                <u> = 2.83</u>

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Answer:

Transverse wave

Explanation:

Its because in transverse wave the particle displacement is perpendicular to the direction of wave propagation..hope it helps you...

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Explain why a moving object cannot come to a stop instantly in zero seconds
sineoko [7]
Well because it has momentum and it needs to be slowed down.
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A wire carries a 2a current. what is the current in a second wire that delivers twice as much charge in the same amount of time?
Soloha48 [4]

Answer:

4A

Explanation:

Current is charge per time.  So if the second wire delivers twice as much charge in the same amount of time, it must have twice the current.

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7 0
3 years ago
If I exert a 203 N force on a 58 kg box, what will the acceleration of the box be?
Anit [1.1K]

Answer:

<h2>3.5 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

m is the mass

f is the force

From the question we have

a =  \frac{203}{58} =  \frac{7}{2}   \\

We have the final answer as

<h3>3.5 m/s²</h3>

Hope this helps you

7 0
3 years ago
A 2.64-kg copper part, initially at 400 K, is plunged into a tank containing 4 kg of liquid water, initially at 300 K. The coppe
marin [14]

Answer:

a) T_f=305.7049\ K

b) \Delta S=313.51\ J.K^{-1}

Explanation:

Given:

  • mass of copper, m_c=2.64\ kg
  • initial temperature of copper, T_{ic}=400\ K
  • specific heat capacity of copper, c_c=385\ J.kg^{-1}.K^{-1}
  • mass of water, m_w=4\ kg
  • initial temperature of water, T_{iw}=300\ K
  • specific heat capacity of water, c_w=4200\ J.kg^{-1}.K^{-1}

a)

<u>∵No heat is lost in the environment and the heat is transferred only between the two bodies:</u>

Heat rejected by the copper = heat absorbed by the water

2.64\times 385\times (400-T_f)= 4\times 4200\times (T_f-300)

T_f=305.7049\ K

b)

<u>Now the amount of heat transfer:</u>

Q=m_c.c_c.(T_{ic}-T_{f})

Q=2.64\times 385\times (400-305.7049)

Q=95841.5841\ J

∴Entropy change

\Delta S=\frac{dQ}{T}

\Delta S=\frac{95841.5841}{305.7049}

\Delta S=313.51\ J.K^{-1}

5 0
4 years ago
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