Answer:
La teoría atómica de Dalton fue el primer intento completo para describir toda la materia en términos de los átomos y sus propiedades.
Dalton basó su teoría en la ley de la conservación de la masa y la ley de la composición constante.
La primera parte de su teoría establece que toda la materia está hecha de átomos, que son indivisibles.
La segunda parte de su teoría establece que todos los átomos de un elemento dado son idénticos en masa y en propiedades.
La tercera parte de su teoría establece que los compuestos son combinaciones de dos o más tipos diferentes de átomos.
La cuarta parte de su teoría establece que una reacción química es un reordenamiento de átomos.
Partes de su teoría tuvieron que ser modificadas con base en el descubrimiento de las partículas subatómicas y los isótopos.
A. Thermal energy good job
The density of a material is an intensive property.
<h3>
What is intensive property?</h3>
An intensive property of matter is one that does not change with the amount of matter. It is a bulk property, which means that it is a physical property that is independent of sample size or mass. An extensive property, on the other hand, is one that is affected by sample size.
<h3>What factors influence an intensive property?</h3>
Intensive properties are those that are determined solely by the characteristics of the material and not by its quantity - for example, density, temperature, refractive index, color, and pressure. Intensive properties are not additive, which means their value does not change when the amount of material is changed.
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The equilibrium constant of the reaction is 282. Option D
<h3>What is equilibrium constant?</h3>
The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.
Concentration of bromine = 0.600 mol /1.000-L = 0.600 M
Concentration of iodine = 1.600 mol/1.000-L = 1.600M
In this case, we must set up the ICE table as shown;
Br2(g) + I2(g) ↔ 2IBr(g)
I 0.6 1.6 0
C -x -x +2x
E 0.6 - x 1.6 - x 1.190
If 2x = 1.190
x = 1.190/2
x = 0.595
The concentrations at equilibrium are;
[Br2] = 0.6 - 0.595 = 0.005
[I2] = 1.6 - 0.595 = 1.005
Hence;
Kc = [IBr]^2/[Br2] [I2]
Kc = ( 1.190)^2/(0.005) (1.005)
Kc = 282
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Uh i did this because it made me curious... i may have done it wrong nothing happened
