Answer:
heptan-3-one and heptan-2-one
Explanation:
In this case, we must remember what the products of this reaction are. An alkyne in the presence of HgSO4 and H2SO4 will produce a ketone. But, in the triple bond, we have two carbons, therefore the carbonyl group can be placed on any of the carbons of the triple bond.
In figure 1 we have the general reaction. At C = O it can be added to the carbon on the left (red carbon) or the carbon on the right (blue carbon).
Following this logic, for 2-heptyne the carbonyl group can be added to carbon 2 producing <u>heptan-2-one</u>. Similarly, the carbonyl group can be added to carbon 3 producing <u>heptan-3-one</u>. (See figure 2)
Two electrons in it's first energy level; eight electrons in it's second energy level; and six valence electrons in it's outermost energy level
Answer: 10.2 grams
Explanation:
The balanced chemical reaction is :
According to the ideal gas equation:
P = Pressure of the gas = 740 torr = 0.97 atm (760torr=1atm)
V= Volume of the gas = 12.0 L
T= Temperature of the gas = 19°C = 292 K 
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas
According to stoichiometry:
2 moles of hydrogen are generated by = 1 mole of 
Thus 0.48 moles of hydrogen are generated by =
moles of
Mass of 
Thus 10.2 grams of are needed to generate 12.0 L of hydrogen gas if the pressure of hydrogen is 740. torr at 19°C
Answer:
"The total pressure in a mixture of gases is equal to the sum of partial pressures of each gas"
Explanation:
Dalton's law of partial pressures state that, in a mixture of gases, the total pressure is equal to the sum of the partial pressure exerted by each gas of the mixture. The equation is:
Total pressure = Partial pressure Gas 1 + Partial pressure Gas 2 + .... + Partial pressure Gas n
To complete the sentence we can say:
"The total pressure in a mixture of gases is equal to the sum of partial pressures of each gas"
