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Thepotemich [5.8K]
3 years ago
14

Which of Kepler's laws describes the speed at which planets travel at different points in their orbit around the Sun?

Physics
2 answers:
marishachu [46]3 years ago
5 0

Answer:   D) The law of equal area and equal time

Explanation:

vagabundo [1.1K]3 years ago
4 0
D. This says the path sweeps out equal segments of the elliptical path in equal times (picture a wedge of a pie shaped like an oval)
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If an object goes through a
aivan3 [116]

Answer:

A, The same amount of gravity

Explanation:

4 0
2 years ago
Two Mississippi companies, Howard Industries and Kuhlman Electric Company, are responsible for most of the transformers and powe
yanalaym [24]
I  think b but  im not sure just helping

5 0
3 years ago
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What other uses does petroleum have besides being used for fuel and lubricants
Alborosie
the answer i think is asphalt and plastic
7 0
3 years ago
Aluminum has a density of
agasfer [191]

<h3><u>Volume is 0.1848 m³</u></h3><h3 />

Explanation:

<h2>Given:</h2>

m = 49.9 kg

ρ = 270 kg/m³

<h2>Required:</h2>

volume

<h2>Equation:</h2>

ρ \:= \:\frac{m}{v}

where: ρ - density

m - mass

v - volume

<h2>Solution:</h2>

Substitute the value of ρ and m

ρ \:= \:\frac{m}{v}

270\: kg/m³\:= \:\frac{49.9\:kg}{v}

(v)\:270\: kg/m³\:= \:49.9\:kg

v\:= \:\frac{49.9\:kg}{270\: kg/m³}

v\:= \:0.1848\:m³

<h2>Final Answer:</h2><h3><u>Volume is 0.1848 m³</u></h3>
3 0
3 years ago
Read 2 more answers
suppose a child walks from the outer edge of a rotating Merry-Go-Round to the inside does angular velocity of the Merry-Go-Round
Akimi4 [234]

Okay here initially child walks on the outer edge of the disc and then started to move inside

So here as the child and Merry go round is an isolated system so there is no external Torque on this system from outside

As here we can see there is external force acting on this system by the hinge of the Merry go round as well as due to gravity so we can not use momentum conservation to solve such type of questions.

But as we can say that there is no external torque on this system about the hinge point so we will use conservation of angular momentum for this system

Here as we know that

\tau = \frac{dL}{dt}

where L = angular momentum

since here torque is ZERO

0 = \frac{dL}{dt}

L = constant

so here we can write initial angular momentum of the system as

L = (I_1 + I_2)*\omega

here we know that

I_1 = moment of inertia of merry go round

I_2 = moment of inertia of child

so here we can say

(I_1 + I_2)* \omega_1 = (I_1 + I_2')\omega_2

so here as the child moves from edge to inside the disc it moment of inertia will decrease because as we know that moment of inertia of child is given as

I_2 = mr^2

here m = mass of child

r = distance of child from center

Since child is moving inside so his distance from center is decreasing

so here moment of inertia of child is decreasing as he starts moving inside

so final angular speed of merry go round will increase as child go inside

\omega_2 = \frac{(I_1 + I_2)*\omega}{(I_1 + I_2')}

so here as

I_2' < I_2

final angular speed will be more than initial speed as child moves inside

3 0
3 years ago
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