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cestrela7 [59]
3 years ago
5

Wegener proposed the continental drift hypotheses suggesting that

Physics
1 answer:
kipiarov [429]3 years ago
3 0
There was a supercontinent called Pangea
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Lourdes mixes several ingredients in a bowl, creating a cake batter. She holds the bowl up and turns it upside down, causing the
sasho [114]

friction and gravity ....................

4 0
2 years ago
Describe what happens to the moving boat when the oars are out of the water and the forward thrust is zero
Tatiana [17]

Answer:

The boat won't be able to move if the oars were out and there was no thruster. If there was a flow of the water then yes there would be a moving boat.

6 0
2 years ago
A sprinter has a mass of 80 kg and a KE of 4000 J. What is the sprinter’s speed?
djyliett [7]
There you go.

Hope this helps!

8 0
3 years ago
Read 2 more answers
HELP ASAP! GIVING BRAINLIEST!
Blababa [14]

Answer:

1. Emma standing on top of mountain

Since she is at the rest position and at some height from the ground so here energy is due to gravitational potential energy

So we have

gravitational potential energy

U = mgH

2. Emma jumping down from mountain top

Due to free fall Emma will start moving with some speed in downwards direction so here we have

KE = \frac{1}{2}mv^2

motion energy

3. tension in rope at Emma’s lowest position

Due to stretch in the rope here position come to the lowest end and speed comes to zero so whole energy is converted into elastic potential energy

U = \frac{1}{2}kx^2

elastic potential energy

4. Emma bouncing back

Due to bouncing back she will again have its kinetic energy with some speed upwards

KE = \frac{1}{2}mv^2

motion energy

8 0
3 years ago
Read 2 more answers
Two forces act on a 41-kg object. One force has magnitude 65 N directed 59° clockwise from the positive x-axis, and the other ha
Genrish500 [490]

Answer:

a = 1.41 m/s²

Explanation:

Given that

mass ,m= 41 kg

F₁ = 65 N , θ = 59°

F₂ = 35 N ,θ = 32°

The component of Force F₁

F₁x= F₁cos59° i

F₁x= 65 x cos59° i = 33.47 i

F₁y= - F₁ sin 59° j

F₁y= - 65 x sin 59° j = - 55.71 j

The component of Force F₂

F₂x= F₂ sin 32° i

F₂x= 35 x sin 32° i = 18.54 i

F₂y=  F₂ cos 32° j

F₂y=  35 x cos 32° j =  29.68 j

The total force F

F= 33.47 i +   18.54 i - 55.71 j +   29.68 j

F= 52.01 i - 26.03 j

The magnitude of the force F

F=\sqrt{52.01^2+26.03 ^2}\ N

F=58.16 N

We know that

F= m a

a= Acceleration

m=mass

58.16 = 41 x a

a = 1.41 m/s²

6 0
3 years ago
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