Nichrome wire. That's the stuff that toasters are made from. The resistance is pretty high, considering the diameter. 1 meter is at about the same guage as that listed below for copper is about 96 ohms.
Most of the time you are trying to use wire with the least resistance.
A meter of copper has a listed resistance of 0.024 ohms / meter. The wire is a 19 guage wire which makes it pretty thin.
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I'm not sure what you are asking. If want the resistance of something in terms of what would increase the resistance of the same material for both calculations then
Rule 1: It you decrease the wire diameter, you increase the resistance
Rule 2: If you increase the length of the wire, you increase the resistance.
Both rules assume you are using something like copper.
It is itself. This question does not make sense.
Answer:
Explanation:
1760 yd/mi / 120 yd/field = 14⅔ fields/mi
The image of the water tower and the houses is in the attachment.
Answer: (a) P = 245kPa;
(b) P = 173.5 kPa
Explanation: <u>Gauge</u> <u>pressure</u> is the pressure relative to the atmospheric pressure and it is only dependent of the height of the liquid in the container.
The pressure is calculated as: P = hρg
where
ρ is the density of the liquid, in this case, water, which is ρ = 1000kg/m³;
When it is full the reservoir contains 5.25×10⁵ kg. So, knowing the density, you know the volume:
ρ = 
V = ρ/m
V = 
V = 525 m³
To know the height of the spherical reservoir, its diameter is needed and to determine it, find the radius:
V = 
![r = \sqrt[3]{ \frac{3}{4\pi } .V}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%7D%7B4%5Cpi%20%7D%20.V%7D)
r = ![\sqrt[3]{\frac{525.3}{4\pi } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B525.3%7D%7B4%5Cpi%20%7D%20%7D)
r = 5.005 m
diameter = 2*r = 10.01m
(a) Height for House A:
h = 15 + 10.01
h = 25.01
P = hρg
P = 25.01.10³.9.8
P = 245.10³ Pa or 245kPa
(b) h = 25 - 7.3
h = 17.71
P = hρg
P = 17.71.1000.9.8
P = 173.5.10³ Pa or 173.5 kPa