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pentagon [3]
2 years ago
7

Consider the reaction.

Physics
2 answers:
Stels [109]2 years ago
7 0

Consider the reaction.

At equilibrium at 600 K, the concentrations are as follows.

[HF] = 5.82 x 10-2 M

[H2] = 8.4 x 10-3 M

[F2] = 8.4 x 10-3 M

What is the value of Keq for the reaction expressed in scientific notation?

2.1 x 10-2  CORRECT

2.1 x 102

1.2 x 103

1.2 x 10-3

Free_Kalibri [48]2 years ago
5 0

2.1 x 102

Is the correct solution for this problem

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How much current is in a circuit that includes a 9-volt battery with a resistance of 3
Darya [45]
Just remember
Voltage = current times resistance

current = voltage over resistance

Current = 9/3 = 3
7 0
3 years ago
A beam of monochromatic light is aimed at a slit of width and forms a diffraction pattern. In which case is the width of the cen
AysviL [449]

When the incident light is yellow the width of the central band greater. Single-wavelength light sources are known as monochromatic lights, where mono stands for one and chroma for color. Monochromatic lights are defined as visible light that falls inside a specific range of wavelengths. It has a wavelength that falls within a constrained wavelength range.

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4 0
2 years ago
A force of 55N accelerates a 7.5kg wagon at 5.3 m/s^2 along a road. How large is the frictional force?
Varvara68 [4.7K]

Answer:

<h2>15.25 N</h2>

Explanation:

       A force of 55\text{ }N is acting on a wagon along the road. The wagon weights 7.5\text{ }kg. Acceleration of the wagon is given as 5.3\text{ }\frac{m}{s^{2}}.

       Consider the block as the system, the forces acting are Frictional force, Gravitational force, Normal reaction and External force applied by us.

       Gravitational Force and Normal Reaction cancel out each other.

       Net External Force = Mass of system/wagon \times Acceleration of wagon

       F_{ext}-F_{friction}=(7.5\text{ }kg)\times(5.3\text{ }\frac{m}{s^{2}})=39.75\text{ }N\\55\text{ }N-F_{friction}=39.75\text{ }N\\F_{friction}=15.25\text{ }N

F_{friction} has a negative sign because it opposes the motion of the wagon.

∴ Frictional Force = 15.25 N

4 0
3 years ago
A chair of weight 100 N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 4
otez555 [7]

Answer:

The normal force will be "122.8 N".

Explanation:

The given values are:

Weight,

W = 100 N

Force,

F = 40 N

Angle,

θ = 35.0°

As we know,

⇒  N=W+FSin \theta

On substituting the given values, we get

⇒      = 100N+40N \ Sin \theta

⇒      =100N+22.8

⇒      =122.8 \ N

7 0
3 years ago
Does the nucleus of an atom have a positive or negative charge?
Flura [38]
A.
because the nucleus contains protons and neutrons BUT neutrons are neutral and protons are positive, so the answer is A 
8 0
3 years ago
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