Ли делать лазерную коррекцию в России и Казахстана в том числе в области образования и культуры и д на русском для
(1,500 meters) x (1 sec / 330 meters) = (4 and 18/33) seconds
(4.55 sec, rounded)
Answer:
An object with a positive acceleration is always increasing it's velocity.
Answer:
Vf = 28 m/s
Explanation:
In order to find the final velocity of the rock, we will use the 3rd equation of motion. The third equation of motion for vertical direction is written as follows:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = height dropped = 40 m
Vf = final velocity of the rock = ?
Vi = Initial Velocity of the rock = 0 m/s (since, rock was initially at rest)
Therefore,
(2)(9.8 m/s²)(40 m) = Vf² - (0 m/s)²
Vf = √(784 m²/s²)
<u>Vf = 28 m/s</u>
Please help The position of masses 4kg, 6kg, 7kg, 10kg, 2kg, and 12kg are (-1,1), (4,2), (-3,-2), (5,-4), (-2,4) and (3,-5) resp
Sophie [7]
Answer:
(1.9756, -2.1951)
Explanation:
The center of mass equation is: 
= 
, where m represents the masses and x represents the position.
In order to find the coordinates of the center of mass, we need to use this equation for both the x-values and the y-values.
<u>x-values:</u>
<u /> = = 
= 
= 
= 1.9756
<u>y-values:</u>
<u />
= 
= 
= 
= 
= -2.1951
<u>center of mass:</u>
(1.9756, -2.1951)
