Answer:
1. Dynamic equilibrium is a equilibrium in which the rate of forward direction is equal to the rate of backward direction. It is represented by a right left arrow.
2) Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
For the given chemical reaction:
![Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons [Fe(SCN)]^{2-}(aq)](https://tex.z-dn.net/?f=Fe%5E%7B3%2B%7D%28aq%29%2BSCN%5E-%28aq%29%5Crightleftharpoons%20%5BFe%28SCN%29%5D%5E%7B2-%7D%28aq%29)
The expression for is written as:
![K_c=\frac{[[Fe(SCN)]^{2-}]}{[Fe^{3+}][SCN^-]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5B%5BFe%28SCN%29%5D%5E%7B2-%7D%5D%7D%7B%5BFe%5E%7B3%2B%7D%5D%5BSCN%5E-%5D%7D)
3) The value of is 1000 , which means the products are more favoured as compared to reactants and that the equilibrium lies more towards product side.
Answer:
* the total mass of the reactants must equal the total mass of the
products (Law of Conservation of Mass)
Chemical Equation something that uses formulas and symbols to
represent the relative amounts of the reactants
and products of a chemical reaction
Explanation:
Answer:
Molality of solution=10.11 m
Explanation:
We are given that
Given mass of KCl(WB)=75.3 g
Given mass of water (WA)=100 g=100/1000=0.1 kg
1 kg=1000 g
Molar mass of H=1.01 g
Molar mass of K=39g
Molar mass of Cl=35.45 g
We have to find the molality of a solution.
Molar mass of KCl(MB)=39+35.45
Molar mass of KCl(MB) =74.45 g
Number of moles of solute (KCl)=
Number of moles of solute (KCl)=
Number of moles of solute (KCl)=1.011 moles
Molality of solution
=
Using the formula
Molality of solution=
Molality of solution=10.11 m
The energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.
