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3 years ago

What are the shapes and locations of s and p orbitals within an atom.

Chemistry

2 answers:

7nadin3 [17]3 years ago

8 0

Answer : The shapes and locations of 's' orbitals within an atom is spherical and around the nucleus respectively and shapes and locations of 'p' orbitals within an atom is dumbbell and around the nucleus respectively.

Explanation :

As we know that there are many sub-levels which are s, p, d, f, g and so on. The sub-level are oriented in three directions along the x, y and z axis.

The 's' sub-level has one orbital that are spherically shaped.

The 'p' sub-level has three orbitals $(p_x,p_y,p_z)$ that are dumbbell shaped.

The 'd' sub-level has five orbitals $(d_{xy},d_{xz},d_{yz}d_{z^2},d_{x^2-y^2})$ that are double-dumbbell shaped.

The 'f' sub-level has seven orbitals $(f_{x(x^2-3y^2)},f_{y(x^2-3z^2)},f_{y(3x^2-3y^2)},f_{xz^2},f_{z^3},f_{yz^2},f_{xyz})$ that are complex flower shaped.

The location of all the sub-levels is around the nucleus.

Hence, the shapes and locations of 's' orbitals within an atom is spherical and around the nucleus respectively and shapes and locations of 'p' orbitals within an atom is dumbbell and around the nucleus respectively.

skad [1K]3 years ago

4 0

The s-orbital is spherical shape like a ring. The s orbitals are non-directional and spherically symmetrical, This means that the probability of finding the electron is same in all directions at a particular distance from the nucleus. The p-orbitals are more like bowling pins. For p-orbitals, there are three possible orientations corresponding to m = -1, 0, +1 values. This means that there are three p - orbitals in each p-subshell. These are designated as px, py and pz.

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3 years ago

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Imagine that A and B are cations and X, Y, and Z are anions, and that the following reactions occur:

Gekata [30.6K]

AX(aq)+BY(aq)→no precipitate
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the answer is
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4 years ago

a sample of helium occupies a volume of 101.2 mL at a pressure of 790 mmHg. at what pressure would the volume be 120 mL?

AveGali [126]

Answer : The final pressure will be, 666.2 mmHg

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$

or,

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure = 790 mmHg

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$790mmHg\times 101.2mL=P_2\times 120mL$

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3 years ago

This graph shows two curves pertaining to a hydrogen s orbital.

fgiga [73]

Answer 1) : According to the complete question attached in the answer,

The radial wave function which is denoted by $R_{nl}(r)$ shown with orange color crosses through zero point. Also, At the the radial nodes, which are spherical shells to some radial distance away from the nucleus there no electron are found.

Also, the radial probability distribution curve denoted as $R^{2}_{nl}(r)$ shown in blue color is observed to touch zero, and shows the place of radial node.

Therefore, the total number of nodes will include both the kinds which has radial and angular nodes which will be represented by 'n'.

It is observed that for any atomic orbital, the total number of nodes will be n-1 .

Considering the s orbital of the hydrogen, which has zero angular momentum (l); (l=0), as it has zero angular nodes.

Hence, there will be only radial nodes, which is

(n−1 = total number of radial nodes in s orbitals)

According to the image, there are 4 radial nodes shown, so n = 5 (as n-1 = 4; therefore, n = 5)

This represents the 5s orbital.

Answer 2) The radial nodes are observed in I'm seeing radial nodes at

$1.9a_{0}$ , $6.4a_{0}$ , $13.9a_{0}$ and $27.0a_{0}$ .

where $a_{0}$ represents the hydorgen bohr atomic radius = 0.0529177 nm

Explanation : It is quite easy to observe the given graph and find out the approximate values of the radial nodes, it does not requires any equation to be solved. Equation can be used to find the radial nodes if it was supplied along with the question. Although by mere speculation one can find out the answer.

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Alexxandr [17]

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