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monitta
3 years ago
9

What are the shapes and locations of s and p orbitals within an atom.

Chemistry
2 answers:
7nadin3 [17]3 years ago
8 0

Answer : The shapes and locations of 's' orbitals within an atom is spherical and around the nucleus respectively and shapes and locations of 'p' orbitals within an atom is dumbbell and around the nucleus respectively.

Explanation :

As we know that there are many sub-levels which are s, p, d, f, g and so on. The sub-level are oriented in three directions along the x, y and z axis.  

The 's' sub-level has one orbital that are spherically shaped.

The 'p' sub-level has three orbitals (p_x,p_y,p_z) that are dumbbell shaped.

The 'd' sub-level has five orbitals (d_{xy},d_{xz},d_{yz}d_{z^2},d_{x^2-y^2}) that are double-dumbbell shaped.

The 'f' sub-level has seven orbitals (f_{x(x^2-3y^2)},f_{y(x^2-3z^2)},f_{y(3x^2-3y^2)},f_{xz^2},f_{z^3},f_{yz^2},f_{xyz}) that are complex flower shaped.

The location of all the sub-levels is around the nucleus.

Hence, the shapes and locations of 's' orbitals within an atom is spherical and around the nucleus respectively and shapes and locations of 'p' orbitals within an atom is dumbbell and around the nucleus respectively.

skad [1K]3 years ago
4 0
The s-orbital is spherical shape like a ring. The s orbitals are non-directional and spherically symmetrical, This means that the probability of finding the electron is same in all directions at a particular distance from the nucleus. The p-orbitals are more like bowling pins. For p-orbitals, there are three possible orientations corresponding to m = -1, 0, +1 values. This means that there are three p - orbitals in each p-subshell. These are designated as px, py<span> and p</span><span>z.</span>
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Plz help with chemistry quiz I’ll mark brainliest
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The answer is:

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7 0
3 years ago
Which ionic compound would you predict to have a higher boiling point: NaBr or
nasty-shy [4]

Answer:

The boiling point of NaBr is higher than that of Na2S

Explanation:

Bromine has higher electronegativity as compared to the sulphur. The ionic strength of the bond formed with Sodium is higher in the NaBr compound. The higher the ionic bond strength the higher will be the boiling point

Also the size of bromine is large as compared to that of sulphur. Large molecules consists of more electron and hence they create der Waals attractive forces due to which the boiling point of compound increases.

Hence, the boiling point of NaBr is higher than that of Na2S

8 0
3 years ago
What are the possible values of ml for an electron in a d orbital?
spin [16.1K]
The correct answer for the question that is being presented above is this one: "-2, -1, 0, 1, 2." T<span>he possible values of ml for an electron in a d orbital are -2, -1, 0, 1, 2. </span>Since the allowed values for mℓ range from −ℓ to +ℓ, once you know the value for ℓ you know the values for mℓ."
3 0
3 years ago
A chemical reaction produces formaldehyde, with a chemical formula of CH2O. Carbon is in Group 4A, oxygen is in Group 6A, and hy
Dahasolnce [82]

This problem is providing a comparison on the atoms forming formaldehyde, CH₂O, in terms of the groups they are in, C in group 4A, O in group 6A and H in group 1A, and it is asking for a description about the bonds once they are bonded in a formal Lewis dot structure.

In such a way, the attached file shows the Lewis dot structure, in which we can find two bonds between the two hydrogen atoms and the carbon one, and also, a double bond between carbon and oxygen.

The aforementioned is explained by bearing to mind the concept of octet, which states that elements in groups 4A, 5A, 6A and 7A are able to complete 8 valence electrons after bonding.

Thus, since carbon is in group 4A we infer it needs 4 more electrons to complete the octet, and that is achieved due to the 4 bonds it is having with the two hydrogen atoms and double bond with the oxygen atom.

In addition, since oxygen is in group 6A, we infer it needs two more electrons to complete its octet, which is attained via the double bond it has with the carbon atom. For hydrogen, however, it can complete one bond at maximum, because it is in group 1A, which means it can complete two valence electrons after bonding.

Learn more:

  • brainly.com/question/10535983
  • brainly.com/question/21089350

4 0
3 years ago
A 15.0 mL solution of Sr(OH)2 is neutralized with 38.5 mL of 0.350 M
Darya [45]

Answer:

Molarity of Sr(OH)₂  = 0.47 M

Explanation:

Given data:

Volume of Sr(OH)₂ = 15.0 mL

Volume of HCl = 38.5 mL (0.0385 L)

Molarity of HCl = 0.350 M

Concentration/Molarity of Sr(OH)₂  = ?

Solution:

Chemical equation:

Sr(OH)₂ + 2HCl     →      SrCl₂ +2H₂O

Number of moles of HCl:

Molarity = number of moles/ volume in L

0.350 M = number of moles/0.0385 L

Number of moles = 0.350 mol/L× 0.0385 L

Number of moles = 0.0135 mol

Now we will compare the moles of HCl with Sr(OH)₂.

                    HCl       :     Sr(OH)₂

                      2         :         1

                   0.0135   :      1/2×0.0135 = 0.007 mol

Molarity/concentration of Sr(OH)₂:

Molarity = number of moles / volume in L

Molarity = 0.007 mol /0.015 L

Molarity = 0.47 M

7 0
3 years ago
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