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nikitadnepr [17]
3 years ago
5

Describe the three values in a learner-centred curriculum that a teacher can use

Chemistry
1 answer:
ad-work [718]3 years ago
3 0

Answer:

to talk in a way that the class can all understand . help them in thing they are falling . and have a good relashaship.

Explanation:

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What are the spectator ions in 2H+ + SO42- + Ca2+ + 21 → CaSO4 + 2H+ + 21-?
ra1l [238]

Answer:

B

Explanation:

8 0
3 years ago
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Go to the Phase Changes tab. Select the particular molecule, and set the temperature to the given values by using the stove to i
Kipish [7]

Answer:

2. Argon at 160K and approximately 6 atm pressure

5. Neon at 50K and approximately 10 atm pressure

6. Water at 894 K and approximately 20 atm pressure

8. Oxygen at 194K and approximately 2 atm pressure

Explanation:

Super critical fluid is formed when temperature rises beyond critical point. The state of molecules can be liquid or gas. The pressure should be above the certain level with an introduction of different gases at minimum of 2 atm pressure.

3 0
3 years ago
The ka value for acetic acid, ch3cooh(aq), is 1.8× 10–5. calculate the ph of a 1.60 m acetic acid solution.
leonid [27]

<span>To determine the pH of the solution given, we make use of the acid equilibrium constant (Ka) given. It is the ratio of the equilibrium concentrations of the dissociated ions and the acid. The dissociation reaction of the CH3COOH acid would be as follows:

</span>CH3COOH = CH3COO- + H+<span>

The acid equilibrum constant would be expressed as follows:

Ka = [H+][</span>CH3COO-] / [CH3COOH] = 1.8× 10^–5

<span>
To determine the equilibrium concentrations we use the ICE table,
         CH3COOH             H+             </span>CH3COO<span>-
I            1.60                    0                     0
C             -x                    +x                   +x
----------------------------------------------------------------
E         1.60-x                   x                     x 

</span>1.8× 10^–5 =  [H+][CH3COO-] / [CH3COOH] <span>
1.8 x 10^-5 = [x][x] / [0.160-x] </span>

Solving for x,

x = 1.69x10^-3 = [H+] = [F-]

pH = -log [H+] = -log [1.69x10^-3] = 2.8

8 0
3 years ago
The ΔH vap of a certain compound is 46.55 kJ⋅ mol−1 and its ΔS vap is 67.37 J⋅mol−1⋅K−1.
arsen [322]

690 Kelvin is the boiling point of this compound.

Explanation:

Enthalpy is the sum of internal energy and the product of pressure and volume that is how much energy is in the substance.

Entropy is the measurement of randomness and measure of thermal energy per unit of temperature.

ΔH vap of compound is 46.55 kJ⋅ mol− or  J.MOL-1

ΔS vap  is 67.37 J⋅mol−1⋅K−1.

The boiling point or temperature can be calculated by the formula:

T= \frac{ΔH vap}{ΔS vap}

T =\frac{46550}{67.37}      

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The boiling point is the temperature when atmospheric temperature gets equal to

4 0
3 years ago
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While hiking in Costa Rica, Bert discovers a new species of arthropod. Which characteristics should he look at to determine in w
alex41 [277]

Answer:

Characteristics outlined below

Explanation:

Anthropods, though they generally possess exoskeleton, segmented bodies and joint appendages, are divided into four (4) groups:

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  • <em>Trilobite</em> (extinct three-headed/lobed marine species)
6 0
3 years ago
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