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Travka [436]
3 years ago
9

A speed bike tops a hill at 3.50 m/s and accelerates steadily down the hill until reaching a speed of 11.4 m/s after 4.20 second

s. How far did the bike travel during this period? Figure your answer to the nearest tenth of a meter.
Physics
1 answer:
k0ka [10]3 years ago
8 0

Answer:

The bike traveled 31.3 meters during this period

Explanation:

A speed bike tops a hill at 3.50 m/s and accelerates steadily down the

hill until reaching a speed of 11.4 m/s after 4.20 seconds

→ The initial speed u = 3.5 m/s

→ The final speed v = 11.4 m/s

→ The time of acceleration t = 4.2 seconds

→ a = \frac{v-u}{t}

Substitute the values above in the rule to find the acceleration a

→ a = \frac{11.4-3.5}{4.2} = 1.88 m/s²

We need to find the distance that the bike traveled during the

acceleration

→ v² = u² + 2 a s, where s is the distance

→ (11.4)² = (3.5)² + 2 (1.88)(s)

→ 129.96 = 12.25 + 3.76 s

Subtract 12.25 from both sides

→ 117.71 = 3.76 s

Divide both sides by 3.76

→ s = 31.3 meters

<em>The bike traveled 31.3 meters during this period</em>

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3 years ago
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nata0808 [166]

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Murljashka [212]

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Gas

If we increase gas production to fill the energy gap left by oil, our known gas reserves only give us just 52 years left.

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Although it’s often claimed that we have enough coal to last hundreds of years, this doesn’t take into account the need for increased production if we run out of oil and gas.

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