Complete question:
A train has an initial velocity of 44m/s and an acceleration of -4m/s². calculate its velocity after 10s ?
Answer:
the final velocity of the train is 4 m/s.
Explanation:
Given;
initial velocity of the train, u = 44 m/s
acceleration of the train, a = -4m/s² (the negative sign shows that the train is decelerating)
time of motion, t = 10 s
let the final velocity of the train = v
The final velocity of the train is calculated using the following kinematic equation;
v = u + at
v = 44 + (-4 x 10)
v = 44 - 40
v = 4 m/s
Therefore, the final velocity of the train is 4 m/s.
 
        
             
        
        
        
Answer:
The angle of recoil electron with respect to incident beam of photon is 22.90°.
Explanation:
Compton Scattering is the process of scattering of X-rays by a charge particle like electron. 
The angle of the recoiling electron with respect to the incident beam is determine by the relation :
  ....(1)
      ....(1)
Here ∅ is angle of recoil electron, θ is the scattered angle, h is Planck's constant,  is mass of electron, c is speed of light and f is the frequency of the x-ray photon.
 is mass of electron, c is speed of light and f is the frequency of the x-ray photon.
We know that, f = c/λ      ......(2)
Here λ is wavelength of x-ray photon.
Rearrange equation (1) with the help of equation (1) in terms of  λ .

Substitute 6.6 x 10⁻³⁴ m² kg s⁻¹ for h, 9.1 x 10⁻³¹ kg for  , 3 x 10⁸ m/s for c, 0.500 x 10⁻⁹ m for λ  and 134° for θ in the above equation.
, 3 x 10⁸ m/s for c, 0.500 x 10⁻⁹ m for λ  and 134° for θ in the above equation.


 = 22.90°
 = 22.90°
 
        
             
        
        
        
Answer:
-67,500 kgm/s
Explanation:
1300 * 20 + 1100 * (-85) = -67,500 kgm/s