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4 years ago

9

An artillery shell is fired at an angle of 26.3 â¦ above the horizontal ground with an initial speed of 1770 m/s. the accelerati

on of gravity is 9.8 m/s 2 . find the total time of flight of the shell, neglecting air resistance. answer in units of min.

1 answer:

SIZIF [17.4K]4 years ago

3 0

T = 2*V₀*sin (α) / g
t = 2*1770*sin (26.3°) / 9.8 ≈ 2*1770*0.443 / 9.8 ≈ 160 s or 2.7 min

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