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bulgar [2K]
4 years ago
9

What is the explanation for this

Physics
1 answer:
Vladimir [108]4 years ago
5 0

Answer:

Opposite to the net force

Explanation:

The frictional force is a constant force that resists the motion of a body.

There are two classifications of frictional force

                       1)  Static friction

                       2)  Kinetic friction

When a force acts on two surfaces that prevent the sliding between them is the static frictional force.

When a force acts on a moving surface that opposes the motion of the surface is called the kinetic friction.

<em>The kinetic frictional force acts in the direction opposite to the motion and  the net force. </em>

The static and kinetic frictions are dimensionally the same quantity only the coefficient of the friction is higher for static friction.

You might be interested in
I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?
Slav-nsk [51]

Answer:

The height from which the egg is dropped is <u>68.54 m</u>.

Explanation:

Given:

Initial velocity of egg is, u=0\ m/s(Dropped means initial velocity is 0)

Time taken is, t=3.74\ s

Acceleration experienced by egg is due to gravity, a=g=9.8\ m/s^2

The height from which the egg is dropped is, d=?

Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.

So, we have the following equation of motion:

d=ut+\frac{1}{2}at^2

Plug in all the given values and solve for 'd'. This gives,

d=0+\frac{1}{2}\times 9.8\times (3.74)^2\\\\d=\frac{1\times 9.8\times 13.9876}{2}\\\\d=\frac{137.078}{2}\\\\d=68.54\ m

Therefore, the height from which the egg is dropped is 68.54 m.

8 0
3 years ago
A. 2kg<br><br> B. 6kg<br><br> C. 8kg<br><br> D. 14kg
Sati [7]

Answer:

A

Explanation:

We know the force is (16N-12), which is 4N, and we know the acceleration is 2 m/s^2. Meaning, we can solve the formula m = F / a (mass equals force divided by acceleration), and we get 2kg.

7 0
3 years ago
what kind of wave would be observed in outer space between planets where there is very little matter?
ddd [48]
Shock waves can be observed in outer space between planets where there is very little matter. Although little, plasma does exist in outer space which allows the waves to travel.
5 0
3 years ago
If you place small pieces of tissue paper near the balloon in Picture 2, they would probably stick to the
pishuonlain [190]

Answer:

The balloon has more negative charges than positive charges. The tissue paper has a neutral charge.The static electricity pulls on the tissue paper lifting it up.

4 0
3 years ago
An electric field of intensity 3.25 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.
jekas [21]

Answer:

\varphi_1= 796.25 N m^2/C

\varphi_2= 0 N m^2/C

\varphi_3=686.1  N m^2/C

Explanation:

From the question we are told that

Electric field of intensity E= 3.25 kN/C

Rectangle parameter Width W=0.350 m  Length L=0.700 m

Angle to the normal \angle=30.5 \textdegree

Generally the equation for Electric flux at parallel to the yz plane \varphi_1 is mathematically given by

\varphi_1=EA cos theta

\varphi_1=3.25* 10^3 N/C * ( 0.350)(0.700) cos 0

\varphi_1= 796.25 N m^2/C

Generally the equation for Electric flux at parallel to xy  plane \varphi_2 is mathematically given by

\varphi_2=EA cos theta

\varphi_2=3.25* 10^3 N/C * ( 0.350)(0.700) cos 90

\varphi_2= 0 N m^2/C

Generally the equation for Electric flux at angle 30 to x plane \varphi_3 is mathematically given by

\varphi_3=EA cos theta

\varphi_3=3.25* 10^3 N/C * ( 0.350)(0.700) cos 30.5

\varphi_3=686.072219  N m^2/C

\varphi_3=686.1  N m^2/C

7 0
3 years ago
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