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2 years ago

10

Which factors are always part of linear motion?

2 answers:

Daniel [21]2 years ago

4 0

Answer:

Explanation:

In linear motion, the directions of all the vectors describing the system are equal and constant which means the objects move along the same axis and do not change direction.

Paha777 [63]2 years ago

3 0

I’m linear motion, the directions of all the vectors describing the system are equal and constant which means the object move along the same axis and do not change directions

Hope this helped

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What is the best definition of luminous?

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the state of giving off light or glow.

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A wave has a frequency of 875 hz and a wavelength of 352 m. At what speed is this wave traveling

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Answer:

308,000 or 30.8×10^3

Explanation:

v=f×lamda

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Two canoeists in identical canoes exert the same effort paddling and hence maintain the same speed relative to the water. One pa

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Answer:

Speed of river is 0.45 m/s

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$v_c$ = Speed of canoe

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$v_r-v_c=-1.9\ m/s$

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$2v_r=0.9\\\Rightarrow v_r=\frac{0.9}{2}\\\Rightarrow v_r=0.45\ m/s$

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Speed of river is 0.45 m/s

Speed of boat is 2.65 m/s

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3 years ago

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If the electron just misses the upper plate as it emerges from the field, find the magnitude of the electric field.

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Answer:

The magnitude of the electric field be 171.76 N/C so that the electron misses the plate.

Explanation:

As data is incomplete here, so by seeing the complete question from the search the data is

vx_0=1.1 x 10^6

ax=0 As acceleration is zero in the horizontal axis so

Equation of motion in horizontal direction is given as

$s_x=v_x_0 t$

$t=\frac{s_x}{v_x}\\t=\frac{2 \times 10^{-2}}{1.1 \times 6}\\t=1.82 \times 10^{-8} s$

Now for the vertical distance

vy_o=0

than the equation of motion becomes

$s_y=v_y_0 t+\frac{1}{2} at^2\\s_y=\frac{1}{2} at^2\\0.5 \times 10^{-2}=\frac{1}{2} a(1.82 \times 10^{-8})^2\\a=3.02 \times 10^{13} m/s^2$

Now using this acceleration the value of electric field is calculated as

$E=\frac{F}{q}\\E=\frac{ma}{q}\\E=\frac{m_ea}{q_e}\\$

Here a is calculated above, m is the mass of electron while q is the charge of electron, substituting values in the equation

$E=\frac{9.1\times 10^{-31} \times 3.02 \times 10^{13} }{1.6 \times 10^{-19}}\\E=171.76 N/C$

So the magnitude of the electric field be 171.76 N/C so that the electron misses the plate.

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3 years ago