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Anastasy [175]
3 years ago
6

Help Please!!

Chemistry
1 answer:
Ivahew [28]3 years ago
7 0

The first answer would be:

Measure the sequence of events on earth over time.

I believe the second answer would be:

The age of earth. ( I say this because geological time is used to describe timing and the relationship of events in earths history)

I’m not sure about number 3 but I hope this was somewhat useful!!

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What are the three states in which most matter occurs
Mrrafil [7]
Solid, liquid, and gas.
4 0
3 years ago
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The table shows the volumes of different samples of liquid? Which sample has the greatest DENSITY.
arlik [135]

Answer:

Maybe B

Explanation:

4 0
3 years ago
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A discharging lead-acid battery is best described as
dalvyx [7]

Answer:

chemical cells that produce an electrical current

Explanation:

lead acid battery is a type of chemical cell, that discharges to produce electrical current.

lead acid battery uses  lead peroxide for the conversion of the chemical energy into electrical power when it is discharging. It is also rechargeable, that is, it can convert electrical energy back to chemical energy during charging.

Thus, a discharging lead acid battery is best described as a chemical cells that produce an electrical current

6 0
3 years ago
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For the following electrochemical reaction: Al3+(aq) + 3e -> Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -> 2F (aq) Calculate
makvit [3.9K]

<u>Answer:</u> The standard electrode potential of the cell is 4.53 V.

<u>Explanation:</u>

We are given:

E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=2.87-(-1.66)=4.53V

Hence, the standard electrode potential of the cell is 4.53 V.

6 0
3 years ago
A blacksmith heated an iron bar to 1445 °C. The blacksmith then tempered the metal by dropping it into 42,800 mL of
Wittaler [7]

Answer:

6626 g

Explanation:

Given that:

Density of water = 1.00 g/ml, volume of water = 42800 ml.

Since density = mass/ volume

mass of water = volume of water * density of water = 42800 ml * 1 g/ml = 42800 g

Initial temperature of water = 22°C and final temperature of water = 45°C.

specific heat capacity for water = 4.184 J/g°C

ΔT water = 45 - 22 = 23°C

For iron:

mass = m,  

specific heat capacity for iron  = 0.444 J/g°C

Initial temperature of iron = 1445°C and final temperature of water = 45°C.

ΔT iron = 45 - 1445 = -1400°C

Quantity of heat (Q) to raised the temperature of a body is given as:

Q = mCΔT

The quantity of heat required to raise the temperature of water is equal to the temperature loss by the iron.

Q water (gain) + Q iron (loss) = 0

Q water = - Q iron

42800 g ×  4.184 J/g°C × 23°C = -m × 0.444 J/g°C × -1400°C

m = 4118729.6/621.6

m = 6626 g

8 0
3 years ago
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