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Ann [662]
3 years ago
8

A container of a mixture of 4 gases has a total pressure of 35.7 kPa. Gas A has a partial pressure of 7.8kPa. Gas B has a partia

l pressure of 3.7 kPa, and Gas C has a pressure of 8.7kPa. What is the partial pressure of Gas D in kPa?
Chemistry
1 answer:
Maurinko [17]3 years ago
4 0

Answer:

partial pressure of gas D Pd = 15.5 kPa

Explanation:

As per the Dalton's law of partial pressure, in a mixture, pressure exerted by each gas when summed gives the total partial pressure exerted by mixture.

P(Total) = P1+P2+P3.....

Given P(Total) = 35.7 kPa

Partial pressure of gas A Pa = 7.8 kPa

Partial pressure of gas B Pb = 3.7 kPa

Partial pressure of gas C Pc =  8.7 kPa

There, Partial pressure of gas D Pd = P(Total) -(Pa+Pb+Pc)

Pd = 35.7-(7.8+3.7+8.7) = 35.7-20.2 kPa = 15.5 kPa

Therefore, partial pressure of gas D Pd = 15.5 kPa

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NemiM [27]

Answer:

It is important to know if a resource is renewable or non-renewable because renewable resources are self-sustaining (unlike non-renewable resources). If a non-renewable resource is used too often, that resource may eventually become non-existant. This can also happen to renewable resources, but it is more difficult.

3 0
2 years ago
How many grams is 6.31 x 1024 molecules of BF3 in scientific notation?
zhannawk [14.2K]

Answer:

6,461.44 sana po makatulong

5 0
2 years ago
How many moles of glucose does 1.2 x 10^24 molecules represent
sammy [17]
<h3>Answer:</h3>

2.0 mol C₆H₁₂O₆

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.2 × 10²⁴ molecules C₆H₁₂O₆ (glucose)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 1.2 \cdot 10^{24} \ molecules \ C_6H_{12}O_6(\frac{1 \ mol \ C_6H_{12}O_6}{6.022 \cdot 10^{23} \ molecules \ C_6H_{12}O_6})
  2. Divide:                                                                                                                      \displaystyle 1.99269 \ mol \ C_6H_{12}O_6

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.99269 mol C₆H₁₂O₆ ≈ 2.0 mol C₆H₁₂O₆

3 0
3 years ago
Which equation shows how to calculate how many grams (g) of KOH would be needed to fully react with 4 mol Mg(OH)2? The balanced
bazaltina [42]
Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
moles KOH ------------------- 4 moles Mg(OH₂)

moles KOH = 4 x 2 / 1

= 8 moles of  KOH

molar mass KOH = 56 g/mol

mass of KOH = n x mm

mass of  KOH = 8 x 56

= 448 g of KOH 

hope this helps!

3 0
3 years ago
Read 2 more answers
What is the molarity of a NaCl solution containing 9.0<br> moles of NaCl in 3.0 L of solution?
ss7ja [257]

Answer:

3 M

Explanation:

Molarity equation: M = n/v

n = moles of solute

v = liters of solution

9 moles of NaCl / 3 L

9/3 = 3 M

4 0
3 years ago
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