Answer:
Si las condiciones para que el magma permanezca líquido no perduran, el magma se enfriará y solidificará en una roca ígnea. Una roca que se enfría en el interior de la Tierra se denomina intrusiva o plutónica y su enfriamiento será muy lento, produciendo una estructura cristalina de granos grueso.
Explanation:
Answer:
The answer is B (25%)
Explanation:
I think the answer is this because it's the smallest value in the options, and if you choose 0% the answer would be wrong.
The difference between the ideal pressure and the pressure calculated by the Van Der Waal equation is 2.08 atm.
<h3>What is the pressure?</h3>
In this problem, we are mandated to obtain the pressure both by the use of the ideal gas equation and then the use of the Van der Walls equation.
Using the idea gas equation;
PV = nRT
P = nRT/V
P = pressure
V = volume
n = number of moles
T = temperature
R = gas constant
P = 1 * 0.082 * (24 + 273)/0.5
P = 48.7 atm
Using the Van Der Wall equation:
P = RT/(V - b) - a /V^2
P = 0.082 * 297/(0.5 - 0.03219) - 1.345/(0.5)^2
P = 24.354/0.46781 - 1.345/ /0.25
P = 52 - 5.38
P = 46.62 atm
The difference between the ideal pressure and the pressure calculated by the Van Der Waal equation is; 48.7 atm - 46.62 atm = 2.08 atm
Learn more about ideal gas equation:brainly.com/question/3637553
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This problem is describing the equilibrium whereby hydrofluoric acid decomposes to hydrogen and fluorine gases at 298 K whose equilibrium constant is 8.70x10⁻³, the equilibrium concentrations of all the reactants are both 1.33x10⁻³ M and asks for the initial concentration of hydrofluoric acid which turns out to be 2.86x10⁻³ M.
Then, we can write the following equilibrium expression for hydrofluoric acid once the change, 
, has taken place:
![[HF]=[HF]_0-2x](https://tex.z-dn.net/?f=%5BHF%5D%3D%5BHF%5D_0-2x)
Now, since both products are 1.33x10⁻³ M we infer the reaction extent is also 1.33x10⁻³ M, and thus, we can calculate the equilibrium concentration of HF via the law of mass action (equilibrium expression):
![8.70x10^{-3}=\frac{(1.33x10^{-3} M)^2}{[HF]} }](https://tex.z-dn.net/?f=8.70x10%5E%7B-3%7D%3D%5Cfrac%7B%281.33x10%5E%7B-3%7D%20M%29%5E2%7D%7B%5BHF%5D%7D%20%7D)
![[HF]=\frac{(1.33x10^{-3} M)^2}{8.70x10^{-3}} }=2.03x10^{-4}M](https://tex.z-dn.net/?f=%5BHF%5D%3D%5Cfrac%7B%281.33x10%5E%7B-3%7D%20M%29%5E2%7D%7B8.70x10%5E%7B-3%7D%7D%20%7D%3D2.03x10%5E%7B-4%7DM)
Finally, the initial concentration of HF is calculated as follows:
![[HF]_0=[HF]+2x=2.033x10^{-4}+2*(1.33x10^{-3})=2.86x10^{-3}M](https://tex.z-dn.net/?f=%5BHF%5D_0%3D%5BHF%5D%2B2x%3D2.033x10%5E%7B-4%7D%2B2%2A%281.33x10%5E%7B-3%7D%29%3D2.86x10%5E%7B-3%7DM)
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