Answer:
reservoirs and flows of the carbon cycle and how human activities
explication :
Today, the carbon cycle is changing. Humans are moving more carbon into the atmosphere from other parts of the Earth system. More carbon is moving to the atmosphere when fossil fuels, like coal and oil, are burned. More carbon is moving to the atmosphere as humans get rid of forests by burning the trees.
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Answer:
337.5m
Explanation:
<u>Kinematics</u>
Under constant acceleration, the kinematic equation holds:
, where "s" is the position at time "t", "a" is the constant acceleration, "
" is the initial velocity, and
is the initial position.
<u>Defining Displacement</u>
Displacement is the difference in positions:
or 



<u>Using known information</u>
Given that the initial velocity is zero ("skier stands at rest"), and zero times anything is zero, and zero plus anything remains unchanged, the equation simplifies further to the following:




So, to find the displacement after 15 seconds, with a constant acceleration of 3.0 m/s², substitute the known values, and simplify:

![\Delta s=\frac{1}{2}(3.0[\frac{m}{s^2}])(15.0[s])^2](https://tex.z-dn.net/?f=%5CDelta%20s%3D%5Cfrac%7B1%7D%7B2%7D%283.0%5B%5Cfrac%7Bm%7D%7Bs%5E2%7D%5D%29%2815.0%5Bs%5D%29%5E2)
![\Delta s=337.5[m]](https://tex.z-dn.net/?f=%5CDelta%20s%3D337.5%5Bm%5D)
The kinetic energy possessed by the man is 517.5 Joules.
<u>Given the following data:</u>
To find the kinetic energy of the man:
Kinetic energy is an energy that is possessed by a physical object or body due to its motion.
Mathematically, kinetic energy is calculated by using the formula;

<u>Where:</u>
- K.E is the kinetic energy.
- M is the mass of an object.
- V is the velocity of an object.
Substituting the given values, we have;
×
× 
× 
<em>Kinetic energy = 517.5 Joules.</em>
Therefore, the kinetic energy possessed by the man is 517.5 Joules.
Read more: brainly.com/question/23153766
Answer: C = Q/4πR
Explanation:
Volume(V) of a sphere = 4πr^3
Charge within a small volume 'dV' is given by:
dq = ρ(r)dV
ρ(r) = C/r^2
Volume(V) of a sphere = 4/3(πr^3)
dV/dr = (4/3)×3πr^2
dV = 4πr^2dr
Therefore,
dq = ρ(r)dV ; dq =ρ(r)4πr^2dr
dq = C/r^2[4πr^2dr]
dq = 4Cπdr
FOR TOTAL CHANGE 'Q', we integrate dq
∫dq = ∫4Cπdr at r = R and r = 0
∫4Cπdr = 4Cπr
Q = 4Cπ(R - 0)
Q = 4CπR - 0
Q = 4CπR
C = Q/4πR
The value of C in terms of Q and R is [Q/4πR]