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s2008m [1.1K]
3 years ago
10

Why does the gravitational force between earth and moon predominate over electrical forces?

Physics
1 answer:
nadezda [96]3 years ago
4 0

Answer:

Because the Earth and the Moon are electrically neutral

Explanation:

The gravitational force between the Earth and the Moon is given by

F=G\frac{mM}{r^2}

where G is the gravitational constant, m is the mass of the Moon, M is the mass of the Earth, r is the distance between the Moon and the Earth. Since both the Earth and the Moon have large masses, m and M are big, so the gravitational force between the two objects is large.

On the contrary, the electrostatic force between the Earth and the Moon is given by

F=k\frac{q_1 q_2}{r^2}

where k is the Coulomb's constant, q1 is the charge of the Moon, q2 is the charge of the Earth, r is the distance between the Moon and the Earth. However, big objects (and planets as well) are electrically neutral, which means that they have zero charge (because if they had charge, they would tend to attract charge of the opposite sign, becoming neutral again). Therefore, the values of q1 and q2 are approximately zero, so the electrostatic force is zero as well.

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A girl is sledding down a slope that is inclined at 30º with respect to the horizontal. The wind is aiding the motion by providi
lapo4ka [179]

Answer:

 travel time is 7.58 s

Explanation:

We must know the acceleration of the sled and the girl, for this we must use Newton's second law

      F = m a

Since this is a vector equation, let's separate it into its xy components, the best selection of the coordinate system is the X axis parallel to the plane and the Y axis perpendicular to it.

In the attached you can see a free body diagram of this situation, let's write Newton's equations on each axis

X axis

      Wx + F - fr = m a            (1)

Axis y

     N- Wy = 0

     N = Wy

Let's use trigonometry to find the weight components

    Wx = W sin θ

    Wy = W cos θ

In addition, the formula for friction force is

    fr = n N

Let's clear the acceleration of equation 1

   

    a = (W sin θ + F - m N) / m

    a = (mg sin θ + F - m mg cos θ) / m

    a = g (sin θ -m cos θ) + F / m

Let's replace and calculate

    a = 9.8 (sin 30 - 0.299 cos 30) + 148 / 75.7

    a = 2.36 + 1.96

    a = 4,317 m / s²

We already have the acceleration, the speed is zero to leave the rest (Vo = 0) and give the length that runs 124 m, let's use the kinematic equations

   x = v₀ t + ½ a t²

   x = ½ a t²

   t² = 2x / a

  t = √ 2x / a

 

Let's calculate

  t = √( 2 124 / 4,317) = √ 57.45

  t = 7.58 s

7 0
3 years ago
Calculate A, E, μ, cv and S for 1 mole of Kr at 298 K and 1 atm (assuming ideal behavior)
vaieri [72.5K]

Answer:

internal energy E 3716.35 j

cv = 12.47 J/K

S = 12.47 J/K

A =  0.29 J

\mu =3716.35 J/mole

Explanation:

given data:

Kr  atomic number = 36

degree of freedom = 3

1) internal energy E = \frac{f}{2} n R T

                                = \frac{3}{2} *1*8.314*298 = 3716.35 j

2) cv = \frac{E}{T}

         = \frac{3716.35}{298} = 12.47 J/K

3) S = cv =\frac{E}{T} = 12.47 J/K

4) A, Halmholtz free energy = E -TS = 37146.35 - 12.47*298 = 0.29 J

5)chemcial potential \mu = \frac{energy}{mole} = 3716.35 J/mole

6 0
3 years ago
Is a pair of sneakers a want or a need? Is the most expensive pair of sneakers a want or a need?
IgorLugansk [536]

Explanation: A sneaker is a want because you don't actually need it to survive

8 0
2 years ago
Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia
Anton [14]

Answer:

91.64 km

91.64 km high material would go on earth if it were ejected with the same speed as on Io.

Explanation:

According to Newton Law of gravitation:

g=\frac{Gm}{r^2}

Where:

G is gravitational constant=6.67*10^{-11} m^3/kg.s^2

For Moon lo g is:

g_M=\frac{6.67*10^{-11}*8.93*10^{22}}{(1821*10^3)^2m^2} \\g_M=1.7962 m/s^2

According to law of conservation of energy

Initial Energy=Final Energy

K.E_i+mgh_i=K.E_f+mgh_f

\frac{1}{2}m(v_0)^2+mgh_o= \frac{1}{2}m(v_f)^2+mgh_f\\At\ maximum\ height\ v_f=0\\\frac{1}{2}m(v_0)^2+0=mgh_f\\v_0=\sqrt{2gh_f}

For Jupiter's moon Io:

Velocity is given by:

v_0_M=\sqrt{2g_Mh_f_M}

For Earth Velocity is given by:

v_0_E=\sqrt{2g_Eh_f_E}

Now:

v_o_M=v_o_E

\sqrt{2g_Mh_f_M}=\sqrt{2g_Eh_f_E}\\h_f_E=\frac{g_Mh_f_M}{g_E}

g_E=9.8 m/s^2

g_m=1.7962 m/s^2, As\ Calculated\ above

h_f_E=\frac{1.7962*500*10^3m}{9.8} \\h_f_E=91642.85 m\\h_f_E=91.64Km

91.64 km high material would go on earth if it were ejected with the same speed as on Io.

8 0
3 years ago
A criminal suspect must be read his or her rights when arrested.this process is referred to as
barxatty [35]
That process is called the Miranda rights
8 0
3 years ago
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