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s2008m [1.1K]
3 years ago
10

Why does the gravitational force between earth and moon predominate over electrical forces?

Physics
1 answer:
nadezda [96]3 years ago
4 0

Answer:

Because the Earth and the Moon are electrically neutral

Explanation:

The gravitational force between the Earth and the Moon is given by

F=G\frac{mM}{r^2}

where G is the gravitational constant, m is the mass of the Moon, M is the mass of the Earth, r is the distance between the Moon and the Earth. Since both the Earth and the Moon have large masses, m and M are big, so the gravitational force between the two objects is large.

On the contrary, the electrostatic force between the Earth and the Moon is given by

F=k\frac{q_1 q_2}{r^2}

where k is the Coulomb's constant, q1 is the charge of the Moon, q2 is the charge of the Earth, r is the distance between the Moon and the Earth. However, big objects (and planets as well) are electrically neutral, which means that they have zero charge (because if they had charge, they would tend to attract charge of the opposite sign, becoming neutral again). Therefore, the values of q1 and q2 are approximately zero, so the electrostatic force is zero as well.

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A person weighing 0.9 kN rides in an elevator that has a downward acceleration of 1.9 m/s^2. The acceleration of gravity is 9.8
Keith_Richards [23]

Answer:

The magnitude of the force is 0.7255kN

Explanation:

The elevator floor acts on the person with a force that is due to the gravitational acceleration less the downward acceleration of the elevator:

(force of floor F) = (mass of person m) x [ (grav. acceleration g) - (elevator acceleration a) ]

in other words, considering the elevator floor as a reference frame in the Earth's gravitational field, the person's weight decreases due to the downward acceleration, as follows:

F = m\cdot(g-a)

We are given the person's weight at rest, 0.9kN, from which the mass can be determined as:

900 N = m\cdot g \implies m = \frac{900N}{9.8 \frac{m}{s^2}}

So

F = \frac{900N}{9.8 \frac{m}{s^2}}\cdot(9.8-1.9)\frac{m}{s^2}\approx 725.5N=0.7255kN

3 0
2 years ago
Find the magnitude: || 5-3i || ...?
____ [38]
The magnitude would be :

\sqrt{5^2 + 3^2}

= √34

Hope this helps
5 0
2 years ago
Which of the following provides evidence that Earth's Moon is rotating and revolving at the same rate?
kkurt [141]

B. We can see only one side of the Moon from Earth.


( we only see one side of the moon because the moon rotates around the Earth)

6 0
3 years ago
How long does it take decaying organisms to transform into fossil fuels?
taurus [48]

Answer:

Millions or hundreds of million of years

Explanation:

It takes a very long time for decaying substances to form fossil fuels. It takes around millions or hundreds of million of years for the transformation to occur. This explains why they aren’t renewable.

Decayed plant materials usually form coal while decayed animal materials form crude oil.

7 0
3 years ago
North Dakota Electric Company estimates its demand trend line​ (in millions of kilowatt​ hours) to​ be: D​ = 75.0 ​+ 0.45​Q, whe
Alborosie

Answer:

The demand forecast for winter is 96.36 millions KWH

The demand forecast for spring is 145.08 millions KWH

The demand forecast for summer is 169.89 millions KWH

The demand forecast for fall is 73.08 millions KWH

Explanation:

Given that,

The demand trend line​ is

D=(75.0+0.45Q)\times multiplicative\ seasonal\ factors

We need to calculate the demand forecast for winter

Using given formula

D=(75.0+0.45Q)\times multiplicative\ seasonal\ factors

Put the value into the formula

D=(75.0+0.45\times101)\times0.80

D=96.36\ millions\ KWH

We need to calculate the demand forecast for spring

Using given formula

D=(75.0+0.45Q)\times multiplicative\ seasonal\ factors

Put the value into the formula

D=(75.0+0.45\times102)\times1.20

D=145.08\ millions\ KWH

We need to calculate the demand forecast for summer

Using given formula

D=(75.0+0.45Q)\times multiplicative\ seasonal\ factors

Put the value into the formula

D=(75.0+0.45\times103)\times1.40

D=169.89\ millions KWH

We need to calculate the demand forecast for fall

Using given formula

D=(75.0+0.45Q)\times multiplicative\ seasonal\ factors

Put the value into the formula

D=(75.0+0.45\times104)\times0.60

D=73.08\ millions KWH

Hence, The demand forecast for winter is 96.36 millions KWH

The demand forecast for spring is 145.08 millions KWH

The demand forecast for summer is 169.89 millions KWH

The demand forecast for fall is 73.08 millions KWH

3 0
3 years ago
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