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s2008m [1.1K]
4 years ago
10

Why does the gravitational force between earth and moon predominate over electrical forces?

Physics
1 answer:
nadezda [96]4 years ago
4 0

Answer:

Because the Earth and the Moon are electrically neutral

Explanation:

The gravitational force between the Earth and the Moon is given by

F=G\frac{mM}{r^2}

where G is the gravitational constant, m is the mass of the Moon, M is the mass of the Earth, r is the distance between the Moon and the Earth. Since both the Earth and the Moon have large masses, m and M are big, so the gravitational force between the two objects is large.

On the contrary, the electrostatic force between the Earth and the Moon is given by

F=k\frac{q_1 q_2}{r^2}

where k is the Coulomb's constant, q1 is the charge of the Moon, q2 is the charge of the Earth, r is the distance between the Moon and the Earth. However, big objects (and planets as well) are electrically neutral, which means that they have zero charge (because if they had charge, they would tend to attract charge of the opposite sign, becoming neutral again). Therefore, the values of q1 and q2 are approximately zero, so the electrostatic force is zero as well.

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PLS ANSWERRR What are the main differences between the carbon flows 300 years ago and today?
cricket20 [7]

Answer:

reservoirs and flows of the carbon cycle and how human activities

explication :

Today, the carbon cycle is changing. Humans are moving more carbon into the atmosphere from other parts of the Earth system. More carbon is moving to the atmosphere when fossil fuels, like coal and oil, are burned. More carbon is moving to the atmosphere as humans get rid of forests by burning the trees.

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6 0
3 years ago
2) A skier stands at rest and begins to ski downhill with an acceleration of 3.0 m/s² {downhill). What is
Finger [1]

Answer:

337.5m

Explanation:

<u>Kinematics</u>

Under constant acceleration, the kinematic equation holds:

s=\frac{1}{2}at^2+v_ot+s_o, where "s" is the position at time "t", "a" is the constant acceleration, "v_o" is the initial velocity, and s_o is the initial position.

<u>Defining Displacement</u>

Displacement is the difference in positions: s-s_o or \Delta s
s=\frac{1}{2}at^2+v_ot+s_o

s-s_o=\frac{1}{2}at^2+v_ot

\Delta s=\frac{1}{2}at^2+v_ot

<u>Using known information</u>

Given that the initial velocity is zero ("skier stands at rest"), and zero times anything is zero, and zero plus anything remains unchanged, the equation simplifies further to the following:

\Delta s=\frac{1}{2}at^2+v_ot

\Delta s=\frac{1}{2}at^2+(0)*t

\Delta s=\frac{1}{2}at^2+0

\Delta s=\frac{1}{2}at^2

So, to find the displacement after 15 seconds, with a constant acceleration of 3.0 m/s², substitute the known values, and simplify:

\Delta s=\frac{1}{2}at^2

\Delta s=\frac{1}{2}(3.0[\frac{m}{s^2}])(15.0[s])^2

\Delta s=337.5[m]

5 0
2 years ago
A 90.0-kg man runs at a constant speed of 11.5 m/s. what is his kinetic energy?
harina [27]

The kinetic energy possessed by the man is 517.5 Joules.

<u>Given the following data:</u>

  • Mass = 90.0 kg
  • Velocity = 11.5 m/s.

To find the kinetic energy of the man:

Kinetic energy is an energy that is possessed by a physical object or body due to its motion.

Mathematically, kinetic energy is calculated by using the formula;

K.E = \frac{1}{2} MV^2

<u>Where:</u>

  • K.E is the kinetic energy.
  • M is the mass of an object.
  • V is the velocity of an object.

Substituting the given values, we have;

K.E = \frac{1}{2} × 90 × 11.5

K.E = 45 × 11.5

<em>Kinetic energy = 517.5 Joules.</em>

Therefore, the kinetic energy possessed by the man is 517.5 Joules.

Read more: brainly.com/question/23153766

8 0
3 years ago
A sphere of radius R has total charge Q. The volume charge density (C/m3) within the sphere is rho(r)=C/r2, where C is a constan
san4es73 [151]

Answer: C = Q/4πR

Explanation:

Volume(V) of a sphere = 4πr^3

Charge within a small volume 'dV' is given by:

dq = ρ(r)dV

ρ(r) = C/r^2

Volume(V) of a sphere = 4/3(πr^3)

dV/dr = (4/3)×3πr^2

dV = 4πr^2dr

Therefore,

dq = ρ(r)dV ; dq =ρ(r)4πr^2dr

dq = C/r^2[4πr^2dr]

dq = 4Cπdr

FOR TOTAL CHANGE 'Q', we integrate dq

∫dq = ∫4Cπdr at r = R and r = 0

∫4Cπdr = 4Cπr

Q = 4Cπ(R - 0)

Q = 4CπR - 0

Q = 4CπR

C = Q/4πR

The value of C in terms of Q and R is [Q/4πR]

7 0
3 years ago
In metal wires the charged particles that move are A. protons B. electrons C. neutrons D. none of the above
VashaNatasha [74]

Answer:

the answer is B: electrons

Explanation:

4 0
4 years ago
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