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Ierofanga [76]
3 years ago
11

the amount of solar energy reaching 1 m² of earths surface each second is 1.366 x 10^3 joules. if this energy was converted into

mass, how much mass in kilograms would be hitting each square meter of earths surface per second
Chemistry
1 answer:
Advocard [28]3 years ago
4 0
I think is 6.588579795x10^13 Kg because the equation is E=mc^2 and E is your Joules and c^2= 9x10^16 so m=(c^2)/E

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If wind is eroding an area at a rate of 2 mm per year and depositing it in a smaller area at a rate of 7 mm per year, how much l
amid [387]

Answer:

After 2000 years, the first after will be 4m lower.

After 2000 years, the second area will be 14m higher.

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From the given information:

At the first area:

if the wind is eroding at 2 mm/year, then after 2000 years; we have:

2 mm/year × 2000 year = 4000 mm

4000 mm to meters, we have:

=4000 \ mm \times \dfrac{1 \ m}{ 1000 \ mm}

= 4 m lower

At the second smaller area:

Given that the wind is depositing it at the rate of 7 mm per year;

Then:

7 mm/year × 2000 year = 14000 mm

=14000 \ mm \times \dfrac{1 \ m}{ 1000 \ mm}

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If I go a distance of 5 meters in 30 seconds, what is my<br> speed
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0.166 m/s

Explanation:

speed = distance / time

= 5 / 30

= 0.166 m/s

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