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3 years ago

8

⦁ The average distance from the sun to the planet Mercury is about 58,000,000 km. The diameter of a human hair is about 0.0025 c

m.
⦁ What is the distance from the sun to Mercury written in scientific notation?
⦁ What is the diameter of a human hair written in scientific notation?
⦁ In comparing the measurements in Parts (a) and (b), what else must be done before a comparison is made?
I have no idea what to answer our teacher hasent taught us this and its overdue please help

2 answers:

dalvyx [7]3 years ago

7 0

Answer:

distance is 5.8x10^7 km

The diameter is 2.5x10^-3 cm

Step-by-step explanation:

Fantom [35]3 years ago

4 0

Answer:

The distance is 5.8x10^7 km

The diameter is 2.5x10^-3 cm

and before a comparison is made both numbers have to be written in the same unit. meaning the km has to be converted to cm or vice versa.

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What is the next term in the following sequence? 12,6,3,...

stira [4]

This sequence keeps dividing by 2. So, you would divide 3 by 2 and you would get 1.5.

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Nat2105 [25]

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We can answer this by applying the rule called "Greater angle, greater side". This is where in any triangle, the opposite side of the larger angle is also longer.

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Therefore, the answer should be AC+BC.

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3 years ago

You make punch for a party. The ratio og ginger ale to fruit juice is 8 cups to 3 cups. You decide to add 4 more cups of ginger

Dvinal [7]

To get the answer we can use proportion
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12 ginger ----------------x
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3 years ago

Help and explain explain !!!!!!!!!!

tigry1 [53]

Answer:

$x=-1\text{ or }x=11$

Step-by-step explanation:

For $a=|b|$ , we have two cases:

$\begin{cases}a=b,\\a=-b\end{cases}$

Therefore, for $18=|15-3x|$ , we have the following cases:

$\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}$

Solving, we have:

$\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}$ .

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3 0

3 years ago

Please help!! MathsWatch, Surd Expressions, Clip 207c

dexar [7]

Answer:

$A=(72+36\sqrt{3})\ mm^2$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

$b=AB+BC+CD+DE$ ----> by segment addition postulate

substitute

$b=3+3+3+3=12\ mm$

step 2

Find the height of rectangle

$a=FB+CG+GH$ ---> by segment addition postulate

substitute the given values

$a=3+CG+3\\a=6+CG$

Find the length sides CG

Applying the Pythagorean Theorem

$BG^2=BC^2+CG^2$

substitute the given values

$6^2=3^2+CG^2$

$CG^2=6^2-3^2$

$CG=\sqrt{27}\ mm$

simplify

$CG=3\sqrt{3}\ mm$

therefore

$a=(6+3\sqrt{3})\ mm$

step 3

Find the area of rectangle

$A=ab$

we have

$a=(6+3\sqrt{3})\ mm$

$b=12\ mm$

substitute

$A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2$

8 0

3 years ago