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ella [17]
3 years ago
7

Which of the following would be the best name for MgCl2?​

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
5 0

Answer:

Magnesium Chloride...

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Which star is the dimmest HELP PLEASE
Len [333]

Answer:

Bellatrix.

Explanation:

8 0
3 years ago
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Blood ph is kept near a value of 7.3 - 7.5 because of
Ede4ka [16]

Answer:  Neutral Value

Explanation:  pH of the blood is maintained at 7.0 to 7.5that is neutral value.

This is because if the pH of the is lower than the maintained value then it will become acidic .

Acidic pH can cause the medical urgency known as acidosis leading to vomiting, diarrhea etc.

If the pH becomes higher, then the blood will become basic in nature and it can also leas to the death of the person.

That is why the pH of the blood is maintianed at neutral value of 7.0 to 7.5

5 0
4 years ago
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After a covalent bond has stabilized an atom, the atom will have
Dafna1 [17]

<em>Answer:</em>

  • The atom have a full valence electron shell.

<em>Explanation:</em>

  • My question is that why covalent bonds take place?

Every atoms tends to from bond with another atoms in order to get nearest electronic configuration of nobel gases. They become stable when their valence shell become complete. So when covelant bond forms between atoms, share electrons to each other and stabilize themselves.

5 0
3 years ago
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3. What is the mass of HI used to create 2.50L of a 0.48 M solution of hydroiodic acid?
Daniel [21]

Answer:

Mass = 153.48 g

Explanation:

Given data:

Volume of solution = 2.50 L

Molarity = 0.48 M

Mass required = ?

Solution:

Molarity = number of moles / volume in litter

Number of moles = Molarity × volume in litter

Number of moles = 0.48 M  × 2.50 L

Number of moles =  1.2 mol

Mass of HI:

Number of moles = mass/molar mass

Mass = Number of moles × molar mass

Mass = 1.2 mol × 127.9 g/mol

Mass = 153.48 g

5 0
3 years ago
An object was measured by a worker as
Gre4nikov [31]

Answer:

\boxed{2.8 \, \%}

Explanation:

\text{Percent error} = \dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \, \%

Data:

Predicted = 17.4 cm

     Actual = 17.9 cm

Calculation:

\text{Percent error} = \dfrac{\lvert 17.4 - 17.9\lvert}{17.9} \times 100 \, \% \\\\= \dfrac{\lvert-0.5\lvert}{17.9} \times 100 \, \% = \dfrac{0.5}{17.9} \times 100 \, \% \\\\= 0.028 \times 100 \, \% = \textbf{2.8 \%}\\\\\text{The percent error in the measurement is } \boxed{\textbf{2.8 \%}}

6 0
3 years ago
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