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tino4ka555 [31]
2 years ago
9

_______are lipids that contain cholesterol

Chemistry
1 answer:
alukav5142 [94]2 years ago
3 0

Answer: Fats

Explanation: Cholesterol is one of several types of fats (lipids) that play an important role in your body.

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AICI3(s)+Ca 3N2(s)-AIN(S)+CaCl2(s)
disa [49]

Answer:

2AlCl3 + Ca3N2 - 2AlN+ 3CaCl2

8 0
2 years ago
what is the  concentration of a NaCl solution, in Molarity, if you add 59.76 g of NaCl into 270 mL of H2O
enot [183]

Hey there!

Molar mass NaCl = 58.44 g/mol

Number of moles

n =  mass of solute / molar mass

n = 59.76 / 58.44

n = 1.0225 moles of NaCl

Volume in liters:

270 mL / 1000 => 0.27 L

Therefore:

M = number of moles / volume ( L )

M = 1.0225 / 0.27

= 3.78 M

Hope that helps!

7 0
3 years ago
The unique odors and flavors of many fruits are primarily due to small quantities of a certain class of organic compounds. The e
SpyIntel [72]
Based on the diagram shown, a numerical setup for calculating the gram-formula mass for reactant 1 would be :
6(1) + 2(12) + 16

Hope this helps
5 0
2 years ago
Quantum transitions that result in the characteristic sharp lines of the X-ray spectrum always involve
labwork [276]

Answer: 5

Explanation: this is because the energy level of the emitted of absorbed photon increases as the number of electron shell decreases, thereby making the inner shell have higher energy than other shells

4 0
3 years ago
Compounds A, B, and C react according to the following equation. 3A(g) + 2B(g) 2C(g) At 100°C a mixture of these gases at equili
Vedmedyk [2.9K]

Answer:

The value of Kc for the reaction is 3.24

Explanation:

A reversible chemical reaction, indicated by a double arrow, occurs in both directions: reagents transforming into products ( direct reaction) and products transforming back into reagents (inverse reaction)

Chemical Equilibrium is the state in which direct and indirect reactions have the same reaction rate. Then taking into account the rate constant of a direct reaction and its inverse the chemical constant Kc is defined.

Being:

aA + bB ⇔ cC + dD

where a, b, c and d are the stoichiometric coefficients, the equilibrium constant with the following equation:

Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }

Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reagents also raised to their stoichiometric coefficients.

Then, in the reaction 3A(g) + 2B(g) ⇔ 2C(g),  the constant Kc is:

Kc=\frac{[C]^{2} }{[A]^{3} *[B]^{2} }

where:

  • [A]= 0.855 M
  • [B]= 1.23 M
  • [C]= 1.75 M

Replacing:

Kc=\frac{1.75^{2} }{0.855^{3}*1.23^{2}  }

Solving you get:

Kc=3.24

<u><em>The value of Kc for the reaction is 3.24</em></u>

8 0
3 years ago
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