Answer:
2255 days
Explanation:
height, h = 1.8 km = 1800 m
amount of water, m = 3.2 x 10^7 kg
Power, P = 2.9 kW = 2900 W
Let t be the time taken
Energy required to lift the water,
E = m g h
E = 3.2 x 10^7 x 9.8 x 1800 = 5.65 x 10^11 J
Power, P = Energy / time
t = E / P = (5.65 x 10^11) / 2900
t = 1.95 x 10^8 second
t = 2255 days
thus, the time taken is 2255 days.
Answer:
t = √2y/g
Explanation:
This is a projectile launch exercise
a) The vertical velocity in the initial instants (
= 0) zero, so let's use the equation
y =
t -1/2 g t²
y= - ½ g t²
t = √2y/g
b) Let's use this time and the horizontal displacement equation, because the constant horizontal velocity
x = vox t
x = v₀ₓ √2y/g
c) Speeds before touching the ground
vₓ = vox = constant
=
- gt
= 0 - g √2y/g
= - √2gy
tan θ = Vy / vx
θ = tan⁻¹ (vy / vx)
θ = tan⁻¹ (√2gy / vox)
d) The projectile is higher than the cliff because it is a horizontal launch
The sun is facing a certain side of the earth
Answer:
Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.
Explanation:
Given:
Speed of sound in air = 320 m/s
Speed of sound in water = 1600 m/s
Time taken to reach certain distance in air = 2.5 sec
a.
We have to find the distance traveled by sound in air.
Distance = Product of speed and time.
⇒ 
⇒ 
⇒
meters.
b.
Now we have to find how much time the sound will take to travel in water.
⇒ Time = Ratio of distance and speed
⇒ 
⇒
<em> ...distance = 800 m and speed = 1600 m/s</em>
⇒ 
⇒
seconds.
Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.
Answer:
A) Towards the sun
Explanation:
The net force is the force of gravity between the Earth and the sun. This force pulls the Earth towards the sun.