fluid friction<span> occurs when an object moves through a liquid or gas. the force needed to overcome </span>fluid friction <span>is usually less then that needed to overcome </span>sliding friction<span>. the </span>fluid<span> keeps the surface from making direct contact and thus </span>reducing friction<span>.</span>
Answer:
m
Explanation:
At 10am, the minute hand and hour hand are ' 2 hours apart', since the minute hand is at 12pm and hour hand is at 10am.
Angle between the two hands = 2/12 * 360
= 60°
Arc Length = 
= 
A current of 0. 82A flows through a light bulb. The charge passed through the light bulb during 94 s is 77.08C
The amount of charge flown for a given period of time determines the current passed through a bulb or electrical body.
The relation between the charge, current and time is given as:
Q = I × t
where, Q is the charge flown through bulb
I is the current passed through bulb
t is the time for which charge passes through bulb
Given,
I = 0.82A
t = 94s
Q = ?
Substituting the values in the above formula:
Q = I × t
Q = 0.82 × 94
Q = 77.08C
Hence, The charge passed through the light bulb during 94 s is 77.08C
Learn more about Current here, brainly.com/question/2264542
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Answer:
The average induced emf in the coil is 0.0286 V
Explanation:
Given;
diameter of the wire, d = 11.2 cm = 0.112 m
initial magnetic field, B₁ = 0.53 T
final magnetic field, B₂ = 0.24 T
time of change in magnetic field, t = 0.1 s
The induced emf in the coil is calculated as;
E = A(dB)/dt
where;
A is area of the coil = πr²
r is the radius of the wire coil = 0.112m / 2 = 0.056 m
A = π(0.056)²
A = 0.00985 m²
E = -0.00985(B₂-B₁)/t
E = 0.00985(B₁-B₂)/t
E = 0.00985(0.53 - 0.24)/0.1
E = 0.00985 (0.29)/ 0.1
E = 0.0286 V
Therefore, the average induced emf in the coil is 0.0286 V
