Question

Look at the data table and graph for the 50-coil electromagnet. With the 1.5 V battery, the electromagnet picked up an average of 13 paper clips, while the 25-coil electromagnet picked up an average of 6 paper clips.a.What is the ratio of the number of turns of the 50-turn electromagnet to the number of turns of the 25-coil electromagnet? b.What is the approximate ratio of the number of paper clips pickedup by the 50-coil electromagnet?

Answer 1

1) The ratio between the number of turns of the two electromagnets is 2

2) The ratio between the number of paper clips picked up is 2.2

Explanation:

1)

An electromagnet is a device consisting of a coil of wire wrapped around an iron core. Such a device is able to create a magnetic field, and in this problem this is used to attract and pick up the paper clips.

In this problem, we have two electromagnets:

- The first one has 50 turns

- The second one has 25 turns

Therefoore, the ratio of the number of turns of the 50-turn electromagnet to the number of turns of the 25-coil electromagnet is:

$\frac{N_1}{N_2}=\frac{50}{25}=2$

2)

The strength of the magnetic field produced by an electromagnet is directly proportional to the number of turns in the coil wrapped on the electromagnet:

$B\propto N$

This means that the electromagnet with more turns will produce a stronger magnetic field, and therefore it will be able to pickup more paper clips.

In this problem, in fact:

- The electromagnet with 50 turns can pick up 13 paper clips

- The electromagnet with 25 turns picks up 6 paper clips

Therefore, the ratio of the number of paper clips picked up is:

$\frac{p_1}{p_2}=\frac{13}{6}=2.2$

And we see that this ratio is approximately equal to the ratio of the number of turns, which is 2.

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