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Fiesta28 [93]
3 years ago
15

An object is 2.0 cm from a double convex lens with a focal length of 1.5 cm. Calculate the image distance

Physics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:

0.857 cm

Explanation:

We are given that:

The focal length for a convex lens to be (f) = 1.5cm

The object distance (u) = - 2.0 cm

We are to determine the image distance (v) = ??? cm

By applying the lens formula:

\dfrac{1}{f} = \dfrac{1}{u}+\dfrac{1}{v}

By rearrangement and making (v) the subject of the above formula:

v = \dfrac{uf}{u-f}

replacing the given values:

v = \dfrac{(-2.0)(1.5)}{(-2.0 -1.5)}

v = \dfrac{-3.0}{(-3.5)}

v = 0.857 cm

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Answer:

The force required to move the quarterback with linebacker is <u>1215 N</u>

Explanation:

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\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}

\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}

Using Newton's second law, it is established that  F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object \left(m_{1}+m_{2}\right)

Now consider both \mathrm{m}_{1} \text { and } \mathrm{m}_{2}as a system, so net force acting on the system is \text { Force }=\left(m_{1}+m_{2}\right) a

Substitute the given values in the above formula,

\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

Force = 1215 N

<u>1215 N </u>is the force required to move the quarterback with linebacker.

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3 years ago
Which point on the standing wave is a node?
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Answer: it’s c

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The suspension system of a 2100 kg automobile "sags" 8.5 cm when the chassis is placed on it. Also, the oscillation amplitude de
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Answer:

Part a)

k = 6.06 \times 10^4 N/m

Part b)

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Explanation:

Part a)

as the mass of the suspension system is given as

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Now we know that amplitude decreases by 63% in each cycle

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so it is given as

A = 0.37 A_o

also we know

A = A_o e^{-bt/2m}

0.37 A_o = A_o e^{-bt/2m}

\frac{bt}{2m} = 1

b = \frac{2m}{t}

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t = 2\pi\sqrt{\frac{m}{k}}

t = 2\pi\sqrt{\frac{525}{6.06 \times 10^4}}

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Answer:

The answer to your question is: F = 70 pounds

Explanation:

To calculate the net force, only substract the left value to the right value.

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